In rhombus JKLM diagonals JL and KM are drawn. If JL = 12 and KM = 16, what is the perI! of JKLM?

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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### Geometry Problem: Finding the Perimeter of a Rhombus

#### Question:
In rhombus JKLΜ, diagonals JL and KM are drawn. If JL = 12 and KM = 16, what is the perimeter of JKLM?

#### Options:
A. 10  
B. 20  
C. 30  
D. 40  

#### Explanation:
To solve for the perimeter of rhombus JKLM, we need to use the relationship between the diagonals and the sides of a rhombus. 

1. In a rhombus, the diagonals bisect each other at right angles.
2. The diagonals of the rhombus create four right-angled triangles, with the diagonals acting as the hypotenuse.

##### Step-by-Step Solution:
1. **Divide the diagonals by 2:**
   - Half of JL = 12 / 2 = 6
   - Half of KM = 16 / 2 = 8

2. **Use the Pythagorean theorem to find the side length of the rhombus:**
   Each side of the rhombus (s) can be found using:
   \[
   s = \sqrt{ (6)^2 + (8)^2 }
   \]
   \[
   s = \sqrt{ 36 + 64 }
   \]
   \[
   s = \sqrt{ 100 }
   \]
   \[
   s = 10
   \]

3. **Calculate the perimeter:**
   Perimeter of the rhombus = 4 * side length
   \[
   \text{Perimeter} = 4 \times 10 = 40
   \]

#### Answer:
D. 40
Transcribed Image Text:### Geometry Problem: Finding the Perimeter of a Rhombus #### Question: In rhombus JKLΜ, diagonals JL and KM are drawn. If JL = 12 and KM = 16, what is the perimeter of JKLM? #### Options: A. 10 B. 20 C. 30 D. 40 #### Explanation: To solve for the perimeter of rhombus JKLM, we need to use the relationship between the diagonals and the sides of a rhombus. 1. In a rhombus, the diagonals bisect each other at right angles. 2. The diagonals of the rhombus create four right-angled triangles, with the diagonals acting as the hypotenuse. ##### Step-by-Step Solution: 1. **Divide the diagonals by 2:** - Half of JL = 12 / 2 = 6 - Half of KM = 16 / 2 = 8 2. **Use the Pythagorean theorem to find the side length of the rhombus:** Each side of the rhombus (s) can be found using: \[ s = \sqrt{ (6)^2 + (8)^2 } \] \[ s = \sqrt{ 36 + 64 } \] \[ s = \sqrt{ 100 } \] \[ s = 10 \] 3. **Calculate the perimeter:** Perimeter of the rhombus = 4 * side length \[ \text{Perimeter} = 4 \times 10 = 40 \] #### Answer: D. 40
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