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In  Reaction 1, you added HCl to your solution of 1.0 M CoCl2.  As mentioned in the lab procedure, HCl is a strong acid, which completely dissociates in water, forming H+ and Cl-.  Using your lab data to help you, answer the following questions below. Co(H2O)6^2+ (aq) + 4 Cl-  <---> CoCl4^2- (aq) + 6H20(I) (Pink)                                                     (blue) Immediately following the addition of HCl to your reaction: The value of Kc will be     (less than/more than/equal)          Qc. Equilibrium will shift to            (reactant/product) After HCl is added, the color of the cobalt solution will          (more pink/more blue/same color)

In  Reaction 1, you added HCl to your solution of 1.0 M CoCl2.  As mentioned in the lab procedure, HCl is a strong acid, which completely dissociates in water, forming H+ and Cl-.  Using your lab data to help you, answer the following questions below. Co(H2O)6^2+ (aq) + 4 Cl-  <---> CoCl4^2- (aq) + 6H20(I) (Pink)                                                     (blue) Immediately following the addition of HCl to your reaction: The value of Kc will be     (less than/more than/equal)          Qc. Equilibrium will shift to            (reactant/product) After HCl is added, the color of the cobalt solution will          (more pink/more blue/same color)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In  Reaction 1, you added HCl to your solution of 1.0 M CoCl2.  As mentioned in the lab procedure, HCl is a strong acid, which completely dissociates in water, forming H+ and Cl-.  Using your lab data to help you, answer the following questions below.

Co(H2O)6^2+ (aq) + 4 Cl-  <---> CoCl4^2- (aq) + 6H20(I)

(Pink)                                                     (blue)

Immediately following the addition of HCl to your reaction:

  • The value of Kc will be     (less than/more than/equal)          Qc.
  • Equilibrium will shift to            (reactant/product)
  • After HCl is added, the color of the cobalt solution will          (more pink/more blue/same color)       .
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