In R3, let S be the set of vectors 3 S = {V1, V2, V3, V4} = -3 -2 -4 -4 a. Explain why S spans R³ but is not a basis for R3. b. Delete one of the vectors from S to form a new set of vectors, that is a basis for R3.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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In \( \mathbb{R}^3 \), let \( S \) be the set of vectors

\[
S = \{ \mathbf{v_1}, \mathbf{v_2}, \mathbf{v_3}, \mathbf{v_4} \} = \left\{
\begin{bmatrix}
-1 \\
4 \\
-4
\end{bmatrix},
\begin{bmatrix}
1 \\
-3 \\
1
\end{bmatrix},
\begin{bmatrix}
1 \\
-2 \\
0
\end{bmatrix},
\begin{bmatrix}
3 \\
0 \\
-4
\end{bmatrix}
\right\}
\]

a. Explain why \( S \) spans \( \mathbb{R}^3 \) but is not a basis for \( \mathbb{R}^3 \).

b. Delete one of the vectors from \( S \) to form a new set of vectors, that is a basis for \( \mathbb{R}^3 \).
Transcribed Image Text:In \( \mathbb{R}^3 \), let \( S \) be the set of vectors \[ S = \{ \mathbf{v_1}, \mathbf{v_2}, \mathbf{v_3}, \mathbf{v_4} \} = \left\{ \begin{bmatrix} -1 \\ 4 \\ -4 \end{bmatrix}, \begin{bmatrix} 1 \\ -3 \\ 1 \end{bmatrix}, \begin{bmatrix} 1 \\ -2 \\ 0 \end{bmatrix}, \begin{bmatrix} 3 \\ 0 \\ -4 \end{bmatrix} \right\} \] a. Explain why \( S \) spans \( \mathbb{R}^3 \) but is not a basis for \( \mathbb{R}^3 \). b. Delete one of the vectors from \( S \) to form a new set of vectors, that is a basis for \( \mathbb{R}^3 \).
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