In questions 1-4, assume that fis a one-to-one function. 1. (a) If f(2)= -5, then what is f-¹(-5)? (b) Iff-¹(6) = 10, then what is f(10)? 2. (a) If f(-1) = 13, then what is f-¹(13)? (b) Iff-¹(b) = a, then what is f(a)?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Therefore, g-¹(x) = -3x + 1 replace y with g-¹(x)
g is a linear function and its domain is x ER and its range is y ER
therefore, for g-¹ the domain is x E R and the range is y ER.
(b) (fog-¹)(x) = f(g-¹(x)) = f(-3x + 1) = 2
2[(-3x + 1) + 4] = 2
-6x + 2 + 8 = 2
Exercise 1.4
-6x = -8
x =
3
In questions 1-4, assume that fis a one-to-one function.
1. (a) Iff(2)= -5, then what is f-¹(-5)?
(b) Iff-¹(6) = 10, then what is f(10)?
2. (a) Iff(-1) = 13, then what is f-¹(13)?
(b) Iff-¹(b) = a, then what is f(a)?
3. If g(x) = 3x - 7, then what is g-¹(5)?
4. If h(x) = x² - 8x, with x ≥ 4, then what is h-¹(-12)?
1
(g) fix1+x
(h) fix-(6-
(i) fix-x²-
(j) fix-
6. Find the invers
(a) f(x) = 2x
(c) f(x) =
(e) f(x)=4-
Use your G
intervals for
all real numbe
value of the
Transcribed Image Text:solved for y Therefore, g-¹(x) = -3x + 1 replace y with g-¹(x) g is a linear function and its domain is x ER and its range is y ER therefore, for g-¹ the domain is x E R and the range is y ER. (b) (fog-¹)(x) = f(g-¹(x)) = f(-3x + 1) = 2 2[(-3x + 1) + 4] = 2 -6x + 2 + 8 = 2 Exercise 1.4 -6x = -8 x = 3 In questions 1-4, assume that fis a one-to-one function. 1. (a) Iff(2)= -5, then what is f-¹(-5)? (b) Iff-¹(6) = 10, then what is f(10)? 2. (a) Iff(-1) = 13, then what is f-¹(13)? (b) Iff-¹(b) = a, then what is f(a)? 3. If g(x) = 3x - 7, then what is g-¹(5)? 4. If h(x) = x² - 8x, with x ≥ 4, then what is h-¹(-12)? 1 (g) fix1+x (h) fix-(6- (i) fix-x²- (j) fix- 6. Find the invers (a) f(x) = 2x (c) f(x) = (e) f(x)=4- Use your G intervals for all real numbe value of the
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