In Problems 25–34, find, if possible, the slope and y-interce i nil the straight line determined by the equation, and sketch the graph. 25. y = 4x - 6 26. x+9 = 2 %3D 27. 3x + 5y - 9 = 0 28. y+4 = 7 29. х 3 -5 30. x -9 = 5y+3 31. y = -2x 32. y - 7= 3(x-4) %3D 33. y = 3 34. 6y - 24 = 0 C um and the
In Problems 25–34, find, if possible, the slope and y-interce i nil the straight line determined by the equation, and sketch the graph. 25. y = 4x - 6 26. x+9 = 2 %3D 27. 3x + 5y - 9 = 0 28. y+4 = 7 29. х 3 -5 30. x -9 = 5y+3 31. y = -2x 32. y - 7= 3(x-4) %3D 33. y = 3 34. 6y - 24 = 0 C um and the
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
Number 27  and number 30 
![FIGURE 3.12 Lines parallel and perpendicular to y = 3x+1 (Example 9).
of a line perpendicular to y = 3x +1 must be - (the negatING res
55.
1
56. Perper
57. Passir
58. Passi
3y =
ng a point-slope form, we get
1
y - (-2) = -÷(x – 3)
3
59. Рass
2x -
y + 2 = -x +1
3
60. Рas.
61. A s
point o
= --x -
62. A
point C
63. S
o laliem at snil vnaet ewollol f
Now Work Problem
tradec
and th
Draw
t passes
and t
with
In Problems 25–34, find, if possible, the slope and y-interce
the straight line determined by the equation, and sketch the
graph.
the s
In F
fol
25. y = 4x – 6
26. x+9 = 2
27. 3x + 5y – 9 = 0
64.
28. y+4 7
has
29. x = -5
ru
30. x- 9 = 5y+3
31. y = -2x
65
32. y -7= 3(x-4)
34. 6y – 24 = 0
de
dicated
33. y = 3
ac
slope-intercept form of the given equation.
35. 2x = 5 – 3y
37. 4x +9y- 5 = 0
ninsdm
36. 5x - 2y 10
38. 3(x – 4) – 7 + 1)=!
39.
2y
3
= -4-
1
40. у 3
300
3
4
parallel](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5543ddee-2505-4f38-aa19-a8acc3b852d3%2F85c04b82-08e5-41b8-82c7-484ad00543aa%2F0yt4ha_processed.jpeg&w=3840&q=75)
Transcribed Image Text:FIGURE 3.12 Lines parallel and perpendicular to y = 3x+1 (Example 9).
of a line perpendicular to y = 3x +1 must be - (the negatING res
55.
1
56. Perper
57. Passir
58. Passi
3y =
ng a point-slope form, we get
1
y - (-2) = -÷(x – 3)
3
59. Рass
2x -
y + 2 = -x +1
3
60. Рas.
61. A s
point o
= --x -
62. A
point C
63. S
o laliem at snil vnaet ewollol f
Now Work Problem
tradec
and th
Draw
t passes
and t
with
In Problems 25–34, find, if possible, the slope and y-interce
the straight line determined by the equation, and sketch the
graph.
the s
In F
fol
25. y = 4x – 6
26. x+9 = 2
27. 3x + 5y – 9 = 0
64.
28. y+4 7
has
29. x = -5
ru
30. x- 9 = 5y+3
31. y = -2x
65
32. y -7= 3(x-4)
34. 6y – 24 = 0
de
dicated
33. y = 3
ac
slope-intercept form of the given equation.
35. 2x = 5 – 3y
37. 4x +9y- 5 = 0
ninsdm
36. 5x - 2y 10
38. 3(x – 4) – 7 + 1)=!
39.
2y
3
= -4-
1
40. у 3
300
3
4
parallel
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