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In Problems 22 through 26, given a piecewise function [(x2+3x-4) (x-1) if x<1 f(x) = kx+1 (2+m)x A) 4 Find lim f(x) =, %3D %3D if x = 1 x→1- if x>1 B) 5 C) 6 D) 7

In Problems 22 through 26, given a piecewise function [(x2+3x-4) (x-1) if x<1 f(x) = kx+1 (2+m)x A) 4 Find lim f(x) =, %3D %3D if x = 1 x→1- if x>1 B) 5 C) 6 D) 7

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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22) In Problems 22 through 26, given a piecewise function (x2+3x-4) (x-1) if x <1 f(x) =, kx+1 (2+m)x A) 4 Find lim f(x) = %3D if x = 1 x→1- if x>1 B) 5 C) 6 D) 7
Transcribed Image Text:22) In Problems 22 through 26, given a piecewise function (x2+3x-4) (x-1) if x <1 f(x) =, kx+1 (2+m)x A) 4 Find lim f(x) = %3D if x = 1 x→1- if x>1 B) 5 C) 6 D) 7
25) Find the value of k = A) 2 such that the function f(x) is continuouos at x = 1. B) 4 C) 3 D) 1 26) Is the function f(x) is continuouos at x =- 5? Explain why. A) No, since f(-5) = - 1; lim f(x) =3, with x→ - 1 lim f(x) z f(-5) ; x→ - 1 B) No, since f(-5) = - 1; lim f(x) = - 2, with X→ - 5 lim f(x) z f(-5) ; x→- 5 C) Yes, since f(-5) = – 1; f(x) = f(-5) ; lim f(x) = 3, with x→- 1 lim x→ - 5 D) Yes, since f(-5) = – 1; lim f(x) = - 1, with lim f(x) = f(-5) ; x→ - 5 x→ - 5
Transcribed Image Text:25) Find the value of k = A) 2 such that the function f(x) is continuouos at x = 1. B) 4 C) 3 D) 1 26) Is the function f(x) is continuouos at x =- 5? Explain why. A) No, since f(-5) = - 1; lim f(x) =3, with x→ - 1 lim f(x) z f(-5) ; x→ - 1 B) No, since f(-5) = - 1; lim f(x) = - 2, with X→ - 5 lim f(x) z f(-5) ; x→- 5 C) Yes, since f(-5) = – 1; f(x) = f(-5) ; lim f(x) = 3, with x→- 1 lim x→ - 5 D) Yes, since f(-5) = – 1; lim f(x) = - 1, with lim f(x) = f(-5) ; x→ - 5 x→ - 5
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