In Problems 2-4, find the domain of each function and evaluate each function at x = -1. 2. f(x) = V4 - 5x 4. h(x) = x-4 x2 + 5x – 36 - :3. g(x) = x + 2 x + 2
In Problems 2-4, find the domain of each function and evaluate each function at x = -1. 2. f(x) = V4 - 5x 4. h(x) = x-4 x2 + 5x – 36 - :3. g(x) = x + 2 x + 2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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how to do 4 please ?
![**Chapter 2: Functions and Their Properties**
In Problems 2-4, find the domain of each function and evaluate each function at \( x = -1 \).
**Problem 2.** \( f(x) = \sqrt{4 - 5x} \)
**Problem 3.** \( g(x) = \frac{x + 2}{|x + 2|} \)
**Problem 4.** \( h(x) = \frac{x - 4}{x^2 + 5x - 36} \)
**Graph Explanation:**
The graph shown is a simple number line centered around 0, with marked points at -4, -2, 2, and 4. It highlights the region around -2 on the vertical axis, possibly indicating a value or location of interest related to the functions or calculations.
For further exploration, students should consider:
- Determining domains by identifying values that cause division by zero or negative values under even roots.
- Evaluating each function at \( x = -1 \) by substituting and simplifying.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0c3597d8-30c2-4840-bf6e-c951942ae65e%2Fcd4c5349-be64-4222-ad0e-dd6318ea6529%2Fil4lc2j2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chapter 2: Functions and Their Properties**
In Problems 2-4, find the domain of each function and evaluate each function at \( x = -1 \).
**Problem 2.** \( f(x) = \sqrt{4 - 5x} \)
**Problem 3.** \( g(x) = \frac{x + 2}{|x + 2|} \)
**Problem 4.** \( h(x) = \frac{x - 4}{x^2 + 5x - 36} \)
**Graph Explanation:**
The graph shown is a simple number line centered around 0, with marked points at -4, -2, 2, and 4. It highlights the region around -2 on the vertical axis, possibly indicating a value or location of interest related to the functions or calculations.
For further exploration, students should consider:
- Determining domains by identifying values that cause division by zero or negative values under even roots.
- Evaluating each function at \( x = -1 \) by substituting and simplifying.
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