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In Problems 1-6, identify the equation as separable, linear, exact, or having an integrating factor that is a function of either x alone or y alone. 1. (2x+yx¯¹) dx + (xy-1) dy = 0 2. 3. (2y³ + 2y²) dx + (3y²x + 2xy) dy = 0 (2x+y) dx + (x-2y) dy = 0 4. (y² + 2xy) dx - x dy = 0 5. (x²sin x+4y) dx + x dy = 0

In Problems 1-6, identify the equation as separable, linear, exact, or having an integrating factor that is a function of either x alone or y alone. 1. (2x+yx¯¹) dx + (xy-1) dy = 0 2. 3. (2y³ + 2y²) dx + (3y²x + 2xy) dy = 0 (2x+y) dx + (x-2y) dy = 0 4. (y² + 2xy) dx - x dy = 0 5. (x²sin x+4y) dx + x dy = 0

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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5,7,9 Please and thank you!! 2.5 EXERCISES In Problems 1-6, identify the equation as separable, linear, exact, or having an integrating factor that is a function of either x alone or y alone. 1. (2x+yx¯¹) dx + (xy-1) dy = 0 2. (2y³ +2y2) dx + (3y²x + 2xy) dy = 0 (2x+y) dx + (x-2y) dy = 0 4. (y² + 2xy) dx-x²¹ dy = 0 3. 5. 6. (x²sin x+4y) dx + x dy = 0 (2x-y) dx + x dy = 0 In Problems 7-12, solve the equation. 7. (2xy) dx + (y² − 3x²) dy = 0 - 8. (3x² + y) dx + (x²y − x) dy = 0 (x¹-x+y) dx − x dy = 0 9. 10
Transcribed Image Text:5,7,9 Please and thank you!! 2.5 EXERCISES In Problems 1-6, identify the equation as separable, linear, exact, or having an integrating factor that is a function of either x alone or y alone. 1. (2x+yx¯¹) dx + (xy-1) dy = 0 2. (2y³ +2y2) dx + (3y²x + 2xy) dy = 0 (2x+y) dx + (x-2y) dy = 0 4. (y² + 2xy) dx-x²¹ dy = 0 3. 5. 6. (x²sin x+4y) dx + x dy = 0 (2x-y) dx + x dy = 0 In Problems 7-12, solve the equation. 7. (2xy) dx + (y² − 3x²) dy = 0 - 8. (3x² + y) dx + (x²y − x) dy = 0 (x¹-x+y) dx − x dy = 0 9. 10
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