In our chemistry laboratory class, the formula for surface tension given is y=mg/2(pi) x r x f where y=surface tension, m= mass of the drop, g= gravitational acceleration, pi is 3.1415, r= outer radius of burette, f=correction factor. Now I searched the internet and it says that the unit for surface tension is kg x m/s^2. The problem is I have grams for the mass of the drop and that the outer radius of the burette is in centimeter while the gravitational acceleration is in meter. What will happen is like this: (1 g x 9.8 m/s^2) / 2 (3.1415) x 0.15 cm x 0.74643 (correction factor no unit) As you can see, if I don't cancel m and cm, the unit will be g x cm x m x s^2. However if change the radius of the burette into meter, it will cancel, the unit will be g x s^2 (missing meter). What can I do to get kg x m/s^2 as the unit for final answer?
In our chemistry laboratory class, the formula for surface tension given is y=mg/2(pi) x r x f where y=surface tension, m= mass of the drop, g= gravitational acceleration, pi is 3.1415, r= outer radius of burette, f=correction factor. Now I searched the internet and it says that the unit for surface tension is kg x m/s^2. The problem is I have grams for the mass of the drop and that the outer radius of the burette is in centimeter while the gravitational acceleration is in meter. What will happen is like this: (1 g x 9.8 m/s^2) / 2 (3.1415) x 0.15 cm x 0.74643 (correction factor no unit) As you can see, if I don't cancel m and cm, the unit will be g x cm x m x s^2. However if change the radius of the burette into meter, it will cancel, the unit will be g x s^2 (missing meter). What can I do to get kg x m/s^2 as the unit for final answer?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In our chemistry laboratory class, the formula for surface tension given is y=mg/2(pi) x r x f where y=surface tension, m= mass of the drop, g= gravitational acceleration, pi is 3.1415, r= outer radius of burette, f=correction factor.
Now I searched the internet and it says that the unit for surface tension is kg x m/s^2. The problem is I have grams for the mass of the drop and that the outer radius of the burette is in centimeter while the gravitational acceleration is in meter. What will happen is like this:
(1 g x 9.8 m/s^2) / 2 (3.1415) x 0.15 cm x 0.74643 (correction factor no unit)
As you can see, if I don't cancel m and cm, the unit will be g x cm x m x s^2. However if change the radius of the burette into meter, it will cancel, the unit will be g x s^2 (missing meter).
What can I do to get kg x m/s^2 as the unit for final answer?
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