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In order to solve with we first After where c is the y' we have 3x² ex 2y-5 the variables. This gives both sides, we obtain y(0) = 1 (2y — 5)dy = (3x² – eª )dx. y² - 5y = x³ e +c of integration. Setting x= Thus, we have y²- 5y- (x³ ex 3) = 0. and

In order to solve with we first After where c is the y' we have 3x² ex 2y-5 the variables. This gives both sides, we obtain y(0) = 1 (2y — 5)dy = (3x² – eª )dx. y² - 5y = x³ e +c of integration. Setting x= Thus, we have y²- 5y- (x³ ex 3) = 0. and

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In order to solve 3x2 y' et 2y – 5 with y(0) = 1 we first the variables. This gives (2y – 5)dy = (3x² – e* )dx. After both sides, we obtain y? – 5y = x – e² +c where c is the of integration. Setting x= and we have . Thus, we have у? — 5у — (23 — e — 3) — 0.
Transcribed Image Text:In order to solve 3x2 y' et 2y – 5 with y(0) = 1 we first the variables. This gives (2y – 5)dy = (3x² – e* )dx. After both sides, we obtain y? – 5y = x – e² +c where c is the of integration. Setting x= and we have . Thus, we have у? — 5у — (23 — e — 3) — 0.
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