In order to keep the songbirds in the back yard happy, one person puts out 14g of seeds at the end of each week. During the week, the birds find and eat 70% of the seeds. The DTDS for the amount of seeds in the back yard at time t where t is measured in weeks and seeds are counted just after a new supply is given by Xi+1 = 0.3x; + 14 . Which of the following is an equation for the general solution of this DTDS, based on an initial seed quantity of 50g? None of the above/below X; = (0.7)'(50) + 50 X, = (0.3)'(30) + 64 X; = (0.3)'(30) + 20 X; = (14)'(50) + 20 X; ミ (0.7)'(30) + 20

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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In order to keep the songbirds in the back yard happy, one person puts out 14g of
seeds at the end of each week. During the week, the birds find and eat 70% of the
seeds. The DTDS for the amount of seeds in the back yard at time t where t is
measured in weeks and seeds are counted just after a new supply is given by
Xt+1 =
0.3х, + 14
Which of the following is an equation for the general solution of this DTDS, based
on an initial seed quantity of 50g?
None of the above/below
Xt =
(0.7)'(50) + 50
Xị = (0.3)'(30) + 64
Xt =
(0.3)'(30) + 20
X; = (14)'(50) + 20
Xị =
(0.7)'(30) + 20
= lx
Transcribed Image Text:In order to keep the songbirds in the back yard happy, one person puts out 14g of seeds at the end of each week. During the week, the birds find and eat 70% of the seeds. The DTDS for the amount of seeds in the back yard at time t where t is measured in weeks and seeds are counted just after a new supply is given by Xt+1 = 0.3х, + 14 Which of the following is an equation for the general solution of this DTDS, based on an initial seed quantity of 50g? None of the above/below Xt = (0.7)'(50) + 50 Xị = (0.3)'(30) + 64 Xt = (0.3)'(30) + 20 X; = (14)'(50) + 20 Xị = (0.7)'(30) + 20 = lx
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