In order to form Ba(IO3)2, 500 mL of 0.5000 M Ba(NO3)2 was mixed with 500 mL of 0.0500 M NaIO3. Ksp= 1.57x10^-9 How many millimoles of Ba(NO3)2 are needed to completely react with NaIO3? What is the limiting reagent? What is the excess reagent?

In order to form Ba(IO3)2, 500 mL of 0.5000 M Ba(NO3)2 was mixed with 500 mL of 0.0500 M NaIO3. Ksp= 1.57x10^-9 How many millimoles of Ba(NO3)2 are needed to completely react with NaIO3? What is the limiting reagent? What is the excess reagent?

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter4: Reactions In Aqueous Solution

Section: Chapter Questions

Problem 78QAP: When 85.0 mL of 0.250 M Ba(OH)2 solution is added to 85.00 mL of 0.250 M Al (NO3)3 solution, a white...

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Question

In order to form Ba(IO₃)₂, 500 mL of 0.5000 M Ba(NO₃)₂ was mixed with 500 mL of 0.0500 M NaIO₃.

Ksp= 1.57x10^-9

How many millimoles of Ba(NO₃)₂ are needed to completely react with NaIO₃?
What is the limiting reagent?
What is the excess reagent?

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