In order to determine the rate law for the decomposition of hydrogen peroxide, a student collected pressure versus time measurements as the hydrogen peroxide decomposed with the addition of KI. The following graph was produced at 21.3 °C. What is the rate of formation of O2? Pressure vs. Time 200 180 y = 1.6212x - 10.899 R2 = 0.919 160 140 120 100 80 60 40 20 20 60 100 120 Time (s) mol L Xs A. 1.62 mol Lxs B. 1.13 x 104 mol L Xs C. 6.74 x10-2 mol L Xs D. 8.83 x 10-5 (Ao) aunssad
In order to determine the rate law for the decomposition of hydrogen peroxide, a student collected pressure versus time measurements as the hydrogen peroxide decomposed with the addition of KI. The following graph was produced at 21.3 °C. What is the rate of formation of O2? Pressure vs. Time 200 180 y = 1.6212x - 10.899 R2 = 0.919 160 140 120 100 80 60 40 20 20 60 100 120 Time (s) mol L Xs A. 1.62 mol Lxs B. 1.13 x 104 mol L Xs C. 6.74 x10-2 mol L Xs D. 8.83 x 10-5 (Ao) aunssad
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:In order to determine the rate law for the decomposition of hydrogen peroxide, a student collected
pressure versus time measurements as the hydrogen peroxide decomposed with the addition of KI. The
following graph was produced at 21.3 °C. What is the rate of formation of O2?
Pressure vs. Time
200
180
y = 1.6212x - 10.899
R? = 0.919
160
140
120
100
80
60
40
20
20
40
60
80
100
120
Time (s)
mol
L XS
A. 1.62
mol
Lxs
В. 1.13 х 104
mol
L Xs
C. 6.74 x10-2
mol
L Xs
D. 8.83 x 10-5
Pressure (torr)
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