In operation an electric toaster has an rms current of 3.95 Awhen plugged into a wall socket with rms voltage 1.20 * 10^2 V. Findthe toaster’s average power
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In operation an electric toaster has an rms current of 3.95 A
when plugged into a wall socket with rms voltage 1.20 * 10^2 V. Find
the toaster’s average power
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- In the circuit diagram R1 = 5R and R2 = 15R, where R = 14 Ω. The power dissipated in resistor 2 is P = 1.6 W. Part (a) What is the voltage across the battery in volts? Part (b) How much power, Ps, is the source supplying, in watts?The figure below shows three lightbulbs connected to a 120-V AC (rms) household supply voltage. Bulbs 1 and 2 have a power rating of 45 W, and bulb 3 has a 100-W rating. 120 V 1 2 3 (a) Find the rms current in each bulb. Ibulb 1 A = Ibulb 2 = A Ibulb 3 = A (b) Find the resistance of each bulb. Ω = 1 R bulb Rbulb 2 = Ω Rbulb 3 Ω = (c) What is the total resistance of the combination of the three lightbulbs? Ω Need Help? Read ItThe figure below shows three lightbulbs connected to a 120-V AC (rms) household supply voltage. Bulbs 1 and 2 have a power rating of 75 W, and bulb 3 has a 40-W rating. 120 V 1 2 3 (a) Find the rms current in each bulb. Ibulb 1 = A Ibulb 2 = A Ibulb 3 = A (b) Find the resistance of each bulb. Ω Rbulb 1 = Rbulb 2 = Ω Rbulb 3 2 i (c) What is the total resistance of the combination of the three lightbulbs? Ω
- An ECG monitor must have an RC time constant less than 1.00 × 102 μs so it can measure variations in voltage over small time intervals. If the resistance of the circuit (due mostly to that of the patient’s chest) is 0.85 kΩ, what is the maximum capacitance of the circuit in F?Consider the combined parallel-series capacitance circuit shown below. C1 C2 60 μ 30 μ C3 40 µF + 6 VThe figure below shows three lightbulbs connected to a 120-V AC (rms) household supply voltage. Bulbs 1 and 2 have a power rating of 100 W, and bulb 3 has a 120-W rating. 120 V 1 2 3 (a) Find the rms current in each bulb. Ipulb 1 = A Ibulb 2 = A Ipulb 3 = A (b) Find the resistance of each bulb. Rbulb 1 = Ω Rpulb 2 = Ω Rpulb 3 = Ω (c) What is the total resistance of the combination of the three lightbulbs?
- A) For the regulation circuit in Fig. below, if {Vz = 5 volt, R:=11 Q, (IL+I2)=0.2A & the unregulated input is Via =16 Volt}. Then, the value of the resistance Rin will be – 0 Lin Rin Unregulated Voltage (Vm) Regulated Voltage (Vz) RL Your answer(a) What is the resistance of a lightbulb that uses an average power of 25.0 W when connected to a 60.0-Hz power source having a maximum voltage of 170 V? Ω (b) What is the resistance of a 75.0-W lightbulb? (Assume the lightbulb uses an average power of 75.0 W when connected to a power source having a maximum voltage of 170 V.) ΩThe figure below shows three lightbulbs connected to a 120-V AC (rms) household supply voltage. Bulbs 1 and 2 have a power rating of 95 W, and bulb 3 has a 45-W rating. (a) Find the rms current in each bulb. Ibulb 1 = Ibulb 2 = Ibulb 3 = (b) Find the resistance of each bulb. Rbulb 1 = Rbulb 2 = Rbulb 3 = (c) What is the total resistance of the combination of the three lightbulbs? Ω