18. b. Test statistic = ?c. P-value = ? d. Reject/Accept null hypothesis ? In one study of smokers who tried to quit smoking with nicotine patch therapy, 35 were smoking one year after treatment and 31 were notsmoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patchtherapy, the majority are smoking one year after the treatment. Do these results suggest that the nicotine patch therapy is not effective?

Given X=35 n=35+31=66 Alpha =0.10

Answered: In one study of smokers who tried to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What is the value of the test statistic for a test with a null hypothesis that mu = 360, Xbar = 350, the sample standard deviation = 20 and n = 49?
can you answer 26a and b
25)
For a one-tailed hypothesis test (upper tail) the p-value is computed to be 0.008. If the test is being conducted at 99% confidence, the null hypothesis could be rejected or not rejected depending on the sample size could be rejected or not rejected depending on the value of the mean of the sample is not rejected is rejected
Which two quantities are needed to estimate the standard error of the proportion‘s toward the further estimation of confidence interval‘s for proportion’s? A) sample mean and sample standard deviation B) sample proportion in sample size C) population proportion in population size D) population mean and population standard deviation ( don't Hand writing solution)
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4. The amount of juice from a dispenser has a normal distribution with a mean of 240ml. A random sample of 10 glasses of juice dispensed from the machine had a mean of 200ml and a standard deviation of 130 ml. A test was carried out at the 5% level of significance to determine if on average the machine does not dispense 240ml of juice. a) State, in symbols, appropriate null and alternative hypothesis for the test. b) Calculate the critical value for the test. c) Calculate the test statistic. d) State, with reason, your decision and conclusion for this test.
The Woodcock-Johnson Cognitive Ability test indicates that the average score is 95. The same group of 12th grade students (n = 72) in Columbus are tested and the sample mean is 110.1 and the sample standard deviation is 15.2. Do the scores provide good evidence that the mean IQ of this population is greater than 95? What is the p-value for this data what is your decision about the null hypothesis? reject or fail to reject?
What is the value of the test statistic for a test with a null hypothesis that mu = 83, Xbar = 85, the sample standard deviation = 2 and n = 49?
What is the value of the test statistic for a test with a null hypothesis that mu = 82, Xbar = 85, the standard error = 5 and n = 100?
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