In one of the labs, a student found the length and width of a rectangular wooden board. The recorded values are as the following: length = 35.7 cm , width = 28.6 cm %3D
In one of the labs, a student found the length and width of a rectangular wooden board. The recorded values are as the following: length = 35.7 cm , width = 28.6 cm %3D
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![In one of the labs, a student found the length and width of a rectangular wooden
board. The recorded values are as the following:
length = 35.7 cm , width = 28.6 cm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbec77771-895c-45f4-8d8c-7b0567db11ab%2Fedcbefd6-6c87-49a1-b4ae-16d459888738%2Fa2n5xgq_processed.png&w=3840&q=75)
Transcribed Image Text:In one of the labs, a student found the length and width of a rectangular wooden
board. The recorded values are as the following:
length = 35.7 cm , width = 28.6 cm
![Question 20
Please select the correct relative uncertainty for both the length and width of the
board using the data from the previous questions from this section:
) Sw/w = 0.003 cm
| 81/1 = 0.0056 cm
O Sw/w = 0.0035 cm
O 8/1 - 0.006
O Sw/w = 0.0035
S/1 = 0.006 cm
| &w/w= 0.003
O 81/1 = 0.0056
Question 21
Working the answers from the previous question, what would be the relative
uncertainty of the area?
0.0091 cm?
0.009
0.0091
O 0.009099
0.009 cm?
O 0.009099 cm?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbec77771-895c-45f4-8d8c-7b0567db11ab%2Fedcbefd6-6c87-49a1-b4ae-16d459888738%2Fkbrjypa_processed.png&w=3840&q=75)
Transcribed Image Text:Question 20
Please select the correct relative uncertainty for both the length and width of the
board using the data from the previous questions from this section:
) Sw/w = 0.003 cm
| 81/1 = 0.0056 cm
O Sw/w = 0.0035 cm
O 8/1 - 0.006
O Sw/w = 0.0035
S/1 = 0.006 cm
| &w/w= 0.003
O 81/1 = 0.0056
Question 21
Working the answers from the previous question, what would be the relative
uncertainty of the area?
0.0091 cm?
0.009
0.0091
O 0.009099
0.009 cm?
O 0.009099 cm?
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