Pls help and code in java!!!! Thank you so much! ### Understanding and Finding the Modular InverseIn many cryptographic applications, the Modular Inverse is a key operation. This programming problem involves finding the modular inverse of a number.#### DefinitionGiven \(0 < x < m\), where x and m are integers, the modular inverse of x is the unique integer n, \(0 < n < m\), such that the remainder upon dividing \(x \times n\) by m is 1. That is,\[x \times n \mod m = 1\]The modular inverse is a concept that extends the arithmetic inverse. For example, the inverse of 2 is \( \frac{1}{2} \) because \( 2 \times \frac{1}{2} = 1 \) with decimal operation. Here the inverse number can be a fraction.In modular inverse, we only allow integers, no fractions. So not all integers have an inverse.#### Examples- For example, \(m = 26, x = 3\): The modular inverse of 3 is 9 because \(3 \times 9 \mod 26 = 1\).- However, \(m = 26, x = 2\): The modular inverse of 2 does not exist because you cannot find a number y so that \(2 \times y \mod 26 = 1\).- Another example, \(m = 17, x = 4\): \(4 \times 13 = 52\). \(52 \mod 17 = 1\), so the remainder when 52 is divided by 17 is 1, and thus 13 is the inverse of 4 modulo 17.#### Problem StatementYou are to write a method `modularInverse()` which accepts as input the two integers x and m, and outputs either the modular inverse n, or -1 to indicate "No such integer exists" if there is no such integer n.You may assume that \(m \leq 100\), x and m are non-negative.#### Example Code```javapublic class ModInverse { public static void main(String[] args) { int m = 26; for (int x = 0; x < m; x++) { int n = modularInverse(x, m); if (n == -1) { System.out.println("The modular inverse of x " + x +

Your java program is given below as you required with an output.

Answered: In many cryptographic applications the…

In many cryptographic applications the Modular Inverse is a key operation. This programming problem involves finding the modular inverse of a number. Given 0

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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