In making wine, glucose (C6H12O6) is fermented to produce ethanol (C2H5OH) and carbon dioxide (CO2) as shown in the reaction. a. If the fermentation reaction starts at 53.2g glucose, what is the theoretical yield of ethanol in grams? b. If 25.8g ethanol is produced, what is the percent yield of the reaction? C6H12O6 -> 2 C2H5OH + 2 CO2 Molar mass of C6H12O6 = 180.156 g/mol Molar mass of C2H5OH = 46.07 g/mol Molar mass of CO2 = 44.01 g/mol
In making wine, glucose (C6H12O6) is fermented to produce ethanol (C2H5OH) and carbon dioxide (CO2) as shown in the reaction. a. If the fermentation reaction starts at 53.2g glucose, what is the theoretical yield of ethanol in grams? b. If 25.8g ethanol is produced, what is the percent yield of the reaction? C6H12O6 -> 2 C2H5OH + 2 CO2 Molar mass of C6H12O6 = 180.156 g/mol Molar mass of C2H5OH = 46.07 g/mol Molar mass of CO2 = 44.01 g/mol
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In making wine, glucose (C6H12O6) is fermented to produce ethanol (C2H5OH) and carbon dioxide (CO2) as shown in the reaction.
a. If the fermentation reaction starts at 53.2g glucose, what is the theoretical yield of ethanol in grams?
b. If 25.8g ethanol is produced, what is the percent yield of the reaction?
C6H12O6 -> 2 C2H5OH + 2 CO2
Molar mass of C6H12O6 = 180.156 g/mol
Molar mass of C2H5OH = 46.07 g/mol
Molar mass of CO2 = 44.01 g/mol
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