In Lamport's Hash we mentioned the notion of using only 64 bits of the hash. At each stage, 128 bits are computed, 64 bits are thrown away, and the hash of the retained 64 bits is used in the next stage. The purpose of only using 64 bits is so that a human does not need to type as long a string. Assuming the person will still only type 64 bits, does it work if hashn does a hash of all 128 bits of hashn-1, but what the person actually transmits is 64 bits of the result?
In Lamport's Hash we mentioned the notion of using only 64 bits of the hash. At each stage, 128 bits are computed, 64 bits are thrown away, and the hash of the retained 64 bits is used in the next stage. The purpose of only using 64 bits is so that a human does not need to type as long a string. Assuming the person will still only type 64 bits, does it work if hashn does a hash of all 128 bits of hashn-1, but what the person actually transmits is 64 bits of the result?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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In Lamport's Hash we mentioned the notion of
using only 64 bits of the hash. At each stage, 128 bits
are computed, 64 bits are thrown away, and the hash of
the retained 64 bits is used in the next stage. The
purpose of only using 64 bits is so that a human does not
need to type as long a string. Assuming the person will
still only type 64 bits, does it work if hashn does a hash
of all 128 bits of hashn-1, but what the person actually
transmits is 64 bits of the result?
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