In integrating the function fx' In Sx dx using integration by parts, what would you choose for your du? x4 dv = dx 4 Option 1 1 dv =- dx Option 2 dv = x3 dx

Q: 3x4-4 cos x = -6

A: Find d2y/dx2 implicitly in terms of x and y3xy − 4 cos x = −6

Q: 3. (y-x)dx = xy (x dx + y dy)

A:

Q: 1. f4x-³ dx -3

A: Find the integral

Q: даду

A:

Q: integrate dx / x^3-x^2  (I do not understand how to set up and complete the A+B+C part

A:

Q: [x' 9 -x dx

A:

Q: For the function f(x) = 3x² In x, find %3D f'(x) = Preview

A: We have to find the derivative of the given function.  For finding the derivative we use product…

Q: Sel+x3/2 Vx dx ,1+3 X,

A:

Q: (x^2 + 4)dy = (2x-8xy)dx

A: Answer

Q: 6/T-9x dx

A: Here we have to integrate        ∫[(6√x - 9x)/x2] dx