The field due to two parallel plates, the left with a negative surface charge density of −6.0 C/m2 whilethe sheet on the right has a positive surface charge density of +9.0 C/m2is given below. Suppose the plates were spaced 0.0020 m apart. We found that, using Gauss’s law that, independent of this distance,• In I the net field points to the left and has magnitude |Enet| = 1.69 × 1011 N/C.• In region II, between the plates, the field has magnitude 8.47×1011 N/C and points to the left• In III it points to the right and has magnitude |Enet| = 1.69 × 1011 N/C. In I the net field points to the left and has magnitude |Enet| = 1,69 × 10¹¹ N/C.• In region II, between the plates, the field has magnitude 8.47 × 10¹¹ N/C and points to the left• In III it points to the right and has magnitude |Enet| = 1,69 × 10¹¹ N/C.·|·|III(a) Plot qualitatively correct E(x) and V(x) graphs, setting V=0 at the left (negatively charged)plate and letting x be the distance from the left plate, with positive x to the right. Use positivevalues for E if it points to the right and negative if it points to the left. Your plot should includethe range of x from -0.002 m to +0.004 m. Check that the direction and size of the slope ofyour V graph is consistent with your E graph values.(b) In what direction would a positive test charge be pushed in each region? Discuss from the pointof view of field and from the point of view of voltage.(c) What would happen in each region to a negative test charge moving to the right? (Would itsspeed increase, decrease, remain the same?)(d) How would your graph change if you chose V=0 to be at the positive plate? Draw that graph.(e) What is the potential difference (AV) between the plates?

Answered: Image /qna-images/answer/18d038f1-7ebe-4b89-9b84-f1b2427519e4.jpg

Answered: • In I the net field points to the left…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Concept explainers

Question

The field due to two parallel plates, the left with a negative surface charge density of −6.0 C/m2 while
the sheet on the right has a positive surface charge density of +9.0 C/m2
is given below. Suppose the plates were spaced 0.0020 m apart. We found that, using Gauss’s law that, independent of this distance,

• In I the net field points to the left and has magnitude |Enet| = 1.69 × 1011 N/C.
• In region II, between the plates, the field has magnitude 8.47×1011 N/C and points to the left
• In III it points to the right and has magnitude |Enet| = 1.69 × 1011 N/C.

In I the net field points to the left and has magnitude |Enet| = 1,69 × 10¹¹ N/C.
• In region II, between the plates, the field has magnitude 8.47 × 10¹¹ N/C and points to the left
• In III it points to the right and has magnitude |Enet| = 1,69 × 10¹¹ N/C.
·|·|
III
(a) Plot qualitatively correct E(x) and V(x) graphs, setting V=0 at the left (negatively charged)
plate and letting x be the distance from the left plate, with positive x to the right. Use positive
values for E if it points to the right and negative if it points to the left. Your plot should include
the range of x from -0.002 m to +0.004 m. Check that the direction and size of the slope of
your V graph is consistent with your E graph values.
(b) In what direction would a positive test charge be pushed in each region? Discuss from the point
of view of field and from the point of view of voltage.
(c) What would happen in each region to a negative test charge moving to the right? (Would its
speed increase, decrease, remain the same?)
(d) How would your graph change if you chose V=0 to be at the positive plate? Draw that graph.
(e) What is the potential difference (AV) between the plates?

Expert Solution

Step 1

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

can someone do e

Solution

by Bartleby Expert

SEE SOLUTION

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions