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In Heat of solution from: Solubility experiment; the slope of plot of Ln S versus 1/T (K-1) = -470 and the intercept = 2.964, calculate the solubility S. gas constant = %3D 8.314 J/mol.K 3.91 O 4.905 O 4.157 O 2.2 O 4.573

In Heat of solution from: Solubility experiment; the slope of plot of Ln S versus 1/T (K-1) = -470 and the intercept = 2.964, calculate the solubility S. gas constant = %3D 8.314 J/mol.K 3.91 O 4.905 O 4.157 O 2.2 O 4.573

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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In Heat of solution from: Solubility experiment; the slope of plot of Ln S versus 1/T (K-1) = -470 and the intercept = 2.964, calculate the %3D solubility S. gas constant = %3D 8.314 J/mol.K 3.91 O 4.905 O 4.157 O 2.2 O 4.573 O
Transcribed Image Text:In Heat of solution from: Solubility experiment; the slope of plot of Ln S versus 1/T (K-1) = -470 and the intercept = 2.964, calculate the %3D solubility S. gas constant = %3D 8.314 J/mol.K 3.91 O 4.905 O 4.157 O 2.2 O 4.573 O
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