In general the current through a capacitor is ic = Cc dt 1. (a) A project engineer received the circuit shown in Fig. P1.1 from his technician who claimed it is a graphic equalizer to provide boost and cut control not just at bass and treble extremes, but also within intermediate frequency bands. The component values are R, = 100 k2, R, = 100 k2, R, = 20 kQ, R = 40 k2, C =1 nF, and C, = 1 nF. (b) (i) Obtain the equations for Vci and VC2 for Fig. P1.1. Note that Vci and VC2 must be functions of Vs, VCı, and vc2 only. (ii) Obtain the SIMULINK simulation block diagram for the equations of (b)(i). i3 HE R R2 i7 io R, is Vs C, 9 V. ER3 Fig. P1.1
In general the current through a capacitor is ic = Cc dt 1. (a) A project engineer received the circuit shown in Fig. P1.1 from his technician who claimed it is a graphic equalizer to provide boost and cut control not just at bass and treble extremes, but also within intermediate frequency bands. The component values are R, = 100 k2, R, = 100 k2, R, = 20 kQ, R = 40 k2, C =1 nF, and C, = 1 nF. (b) (i) Obtain the equations for Vci and VC2 for Fig. P1.1. Note that Vci and VC2 must be functions of Vs, VCı, and vc2 only. (ii) Obtain the SIMULINK simulation block diagram for the equations of (b)(i). i3 HE R R2 i7 io R, is Vs C, 9 V. ER3 Fig. P1.1
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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In general the current through a capacitor is ic =C•
dt
1.
(a) A project engineer received the circuit shown in Fig. P1.1 from his technician who claimed it is a
graphic equalizer to provide boost and cut control not just at bass and treble extremes, but also
within intermediate frequency bands. The component values are R, = 100 k2, R,
= 100 k2, R, = 20
k2, R, = 40 kN, C, = 1 nF, and C, = 1 nF.
(b) (i) Obtain the equations for
and
for
VC2
Fig. P1.1. Note that
and
VC2
must be functions of
Vs, VCı» and vc2 only.
(ii) Obtain the SIMULINK simulation block diagram for the equations of (b)(i).
i3
R,
i2 R,
R, i6
+
+
Vs
C,
Vo
Fig. P1.1
[Hint: vci = Ss(V,»vc1-'cz)dt and vcz = f/(V, VC1+°c2)dt ]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0bbc843f-00bd-48d1-a215-73d6f0d20be9%2F6f3556e6-cf8d-46d7-9167-bda07b00765a%2Fj325ca_processed.jpeg&w=3840&q=75)
Transcribed Image Text:dvc
In general the current through a capacitor is ic =C•
dt
1.
(a) A project engineer received the circuit shown in Fig. P1.1 from his technician who claimed it is a
graphic equalizer to provide boost and cut control not just at bass and treble extremes, but also
within intermediate frequency bands. The component values are R, = 100 k2, R,
= 100 k2, R, = 20
k2, R, = 40 kN, C, = 1 nF, and C, = 1 nF.
(b) (i) Obtain the equations for
and
for
VC2
Fig. P1.1. Note that
and
VC2
must be functions of
Vs, VCı» and vc2 only.
(ii) Obtain the SIMULINK simulation block diagram for the equations of (b)(i).
i3
R,
i2 R,
R, i6
+
+
Vs
C,
Vo
Fig. P1.1
[Hint: vci = Ss(V,»vc1-'cz)dt and vcz = f/(V, VC1+°c2)dt ]
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