In fruit flies, sex is determined by the ratio of X chromosomes to autosomes. What would be the phenotype of a fly that is XXY with 4 sets of autosomes (AAAA)? Male Metafemale
In fruit flies, sex is determined by the ratio of X chromosomes to autosomes. What would be the phenotype of a fly that is XXY with 4 sets of autosomes (AAAA)? Male Metafemale
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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![**Understanding Sex Determination in Fruit Flies**
In fruit flies (Drosophila melanogaster), sex is determined by the ratio of X chromosomes to sets of autosomes. Autosomes are chromosomes that are not sex chromosomes.
### Question:
**What would be the phenotype of a fly that is XXY with 4 sets of autosomes (AAAA)?**
### Options:
- Male
- Metafemale
- Metamale
- Intersex
### Explanation:
To determine the phenotype, calculate the ratio of X chromosomes to sets of autosomes.
In this case:
- The fly has 2 X chromosomes (since the chromosomal configuration is XXY).
- The fly has 4 sets of autosomes (AAAA).
The ratio is calculated as:
\[ \text{Ratio} = \frac{\text{Number of X Chromosomes}}{\text{Number of Sets of Autosomes}} = \frac{2}{4} = 0.5 \]
### Possible Phenotypes Based on Ratio:
1. **Male**: If the ratio is 0.5
2. **Female**: If the ratio is 1.0
3. **Intersex**: Between male and female
4. **Metamale**: If the ratio is significantly lower than 0.5
5. **Metafemale**: If the ratio is significantly higher than 1.0
### Answer:
Since the calculated ratio is 0.5, the phenotype of a fly that is XXY with 4 sets of autosomes (AAAA) would be:
- **Male**
This understanding helps elucidate the intricacies of genetic determination in living organisms, providing a concrete example of how genetic configurations can influence an organism's development.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf32fb61-51c8-4e43-aab8-979b670ff6f9%2Feb2cb922-73d2-41bd-a46b-6f23083e98d2%2Ffbbjh5_processed.png&w=3840&q=75)
Transcribed Image Text:**Understanding Sex Determination in Fruit Flies**
In fruit flies (Drosophila melanogaster), sex is determined by the ratio of X chromosomes to sets of autosomes. Autosomes are chromosomes that are not sex chromosomes.
### Question:
**What would be the phenotype of a fly that is XXY with 4 sets of autosomes (AAAA)?**
### Options:
- Male
- Metafemale
- Metamale
- Intersex
### Explanation:
To determine the phenotype, calculate the ratio of X chromosomes to sets of autosomes.
In this case:
- The fly has 2 X chromosomes (since the chromosomal configuration is XXY).
- The fly has 4 sets of autosomes (AAAA).
The ratio is calculated as:
\[ \text{Ratio} = \frac{\text{Number of X Chromosomes}}{\text{Number of Sets of Autosomes}} = \frac{2}{4} = 0.5 \]
### Possible Phenotypes Based on Ratio:
1. **Male**: If the ratio is 0.5
2. **Female**: If the ratio is 1.0
3. **Intersex**: Between male and female
4. **Metamale**: If the ratio is significantly lower than 0.5
5. **Metafemale**: If the ratio is significantly higher than 1.0
### Answer:
Since the calculated ratio is 0.5, the phenotype of a fly that is XXY with 4 sets of autosomes (AAAA) would be:
- **Male**
This understanding helps elucidate the intricacies of genetic determination in living organisms, providing a concrete example of how genetic configurations can influence an organism's development.
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