In Figure (a), string 1 has a linear density of 1.49 g/m, and string 2 has a linear density of 4.83 g/m. They are under tension due to th hanging block of mass M = 381 g. Calculate the wave speed on (a) string 1 and (b) string 2. (Hint: When a string loops halfway arour pulley, it pulls on the pulley with a net force that is twice the tension in the string.) Next the block is divided into two blocks (with M M2 = M) and the apparatus is rearranged as shown in Figure (b). Find (c) M1 and (d) M2 such that the wave speeds in the two string equal. String I String 2
In Figure (a), string 1 has a linear density of 1.49 g/m, and string 2 has a linear density of 4.83 g/m. They are under tension due to th hanging block of mass M = 381 g. Calculate the wave speed on (a) string 1 and (b) string 2. (Hint: When a string loops halfway arour pulley, it pulls on the pulley with a net force that is twice the tension in the string.) Next the block is divided into two blocks (with M M2 = M) and the apparatus is rearranged as shown in Figure (b). Find (c) M1 and (d) M2 such that the wave speeds in the two string equal. String I String 2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:In Figure (a), string 1 has a linear density of 1.49 g/m, and string 2 has a linear density of 4.83 g/m. They are under tension due to the
hanging block of mass M = 381 g. Calculate the wave speed on (a) string 1 and (b) string 2. (Hint: When a string loops halfway around a
pulley, it pulls on the pulley with a net force that is twice the tension in the string.) Next the block is divided into two blocks (with M1 +
M2 = M) and the apparatus is rearranged as shown in Figure (b). Find (c) M1 and (d) M2 such that the wave speeds in the two strings are
equal.
- String 1
String 2
Knot
(a)
- String 1
String 2
M2
(b)
(a) Number
i
Units
(b) Number
i
Units
(c) Number
i
Units
(d) Number
i
Units
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