In Figure (a), a particle of charge +e is initially at coordinate z = 20 nm on the dipole axis through an electric dipole, on the positive side of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -20 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle e that locates the particle. The scale of the vertical axis is set by Was = 8.0 × 10-30 J. What is the magnitude of the dipole moment? te O +0 -Was (a) (b) Number i Units W. (10-30 J)
In Figure (a), a particle of charge +e is initially at coordinate z = 20 nm on the dipole axis through an electric dipole, on the positive side of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -20 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle e that locates the particle. The scale of the vertical axis is set by Was = 8.0 × 10-30 J. What is the magnitude of the dipole moment? te O +0 -Was (a) (b) Number i Units W. (10-30 J)
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Transcribed Image Text:In Figure (a), a particle of charge +e is initially at coordinate z =
side of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center
until it is at coordinate z = -20 nm. Figure (b) gives the work W, done by the force moving the particle versus the angle 0 that locates
the particle. The scale of the vertical axis is set by Was = 8.0 × 10-30 J. What is the magnitude of the dipole moment?
20 nm on the dipole axis through an electric dipole, on the positive
te
-Was
(a)
(b)
Number
Units
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