In Exercises 9 and 10, (a) express ôw/ðu and ởw/dv as functions of u and v both by using the Chain Rule and by expressing w directly in terms of u and v before differentiating. Then (b) evaluate ôw/du and ôw/dv at the given point (u, v). 9. w = xy + yz + xz, x = u + v, y = u – v, z = uv; (u, v) = (1/2, 1) 10. w = In (x² + y² + z²), x = ue" sin u, y = ue" cos u, z = ue"; (u, v) = (-2, 0)
In Exercises 9 and 10, (a) express ôw/ðu and ởw/dv as functions of u and v both by using the Chain Rule and by expressing w directly in terms of u and v before differentiating. Then (b) evaluate ôw/du and ôw/dv at the given point (u, v). 9. w = xy + yz + xz, x = u + v, y = u – v, z = uv; (u, v) = (1/2, 1) 10. w = In (x² + y² + z²), x = ue" sin u, y = ue" cos u, z = ue"; (u, v) = (-2, 0)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In Exercises 9 and 10, (a) express
![In Exercises 9 and 10, (a) express ôw/ðu and ởw/dv as functions of u
and v both by using the Chain Rule and by expressing w directly in
terms of u and v before differentiating. Then (b) evaluate ôw/du and
ôw/dv at the given point (u, v).
9. w = xy + yz + xz, x = u + v, y = u – v, z = uv;
(u, v) = (1/2, 1)
10. w = In (x² + y² + z²), x = ue" sin u, y = ue" cos u,
z = ue"; (u, v) = (-2, 0)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad153a8a-2318-4f42-8c16-a112ed8847a3%2F65d22580-5dd4-4f03-859e-8ba4389b88a2%2Fvzsr2.png&w=3840&q=75)
Transcribed Image Text:In Exercises 9 and 10, (a) express ôw/ðu and ởw/dv as functions of u
and v both by using the Chain Rule and by expressing w directly in
terms of u and v before differentiating. Then (b) evaluate ôw/du and
ôw/dv at the given point (u, v).
9. w = xy + yz + xz, x = u + v, y = u – v, z = uv;
(u, v) = (1/2, 1)
10. w = In (x² + y² + z²), x = ue" sin u, y = ue" cos u,
z = ue"; (u, v) = (-2, 0)
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