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In Exercises 45-46, we demonstrate that, in general, you antiderivative of a product of functions by taking a prod tives of each. 45. Show that G(x) = x²e* is not an antiderivative of H(x) = 2xe* - 2e* is. 46. Show that G(x) = 3x² sinx is not an antideriv 6x cos x but H(x) = 6x sin x + 6 cos x is. In Exercises 47-60, solve the initial value problem. dy dx 47) 49. 50. 51. (53. 54. ale ale ale ale ale dy dt dy dx dy dt dx = x³, y(0) = 4 dy (6.0) 001 to ovi = 2t +9t², y(1) = 2 dy 48. 184,80 dt = 8x³ + 3x², y(2) = 0 = √t, y(1) = 1 (0)1-(0) 52. 0015 = (4t+3)-2, y(1) = 0 dz dy = (3x+2)³, y(0)=1, ai sgasto isto goini art of his to bong - dt = 3 = t

In Exercises 45-46, we demonstrate that, in general, you antiderivative of a product of functions by taking a prod tives of each. 45. Show that G(x) = x²e* is not an antiderivative of H(x) = 2xe* - 2e* is. 46. Show that G(x) = 3x² sinx is not an antideriv 6x cos x but H(x) = 6x sin x + 6 cos x is. In Exercises 47-60, solve the initial value problem. dy dx 47) 49. 50. 51. (53. 54. ale ale ale ale ale dy dt dy dx dy dt dx = x³, y(0) = 4 dy (6.0) 001 to ovi = 2t +9t², y(1) = 2 dy 48. 184,80 dt = 8x³ + 3x², y(2) = 0 = √t, y(1) = 1 (0)1-(0) 52. 0015 = (4t+3)-2, y(1) = 0 dz dy = (3x+2)³, y(0)=1, ai sgasto isto goini art of his to bong - dt = 3 = t

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How do you solve the initial value for problem 53? Thanks!
antiderivative tives of each. In Exercises 45-46, we demonstrate that, in general, you of a product of functions by taking a prod 45. Show that G(x) = x²ex is not an antiderivative of H(x) = 2xe* - 2et is. 46. Show that G(x) = 3x² sinx is not an antideriv 6x cos x but H(x) = 6x sin x + 6 cos x is. In Exercises 47-60, solve the initial value problem. dy dx 47. 49. 50. 51. (53. 54. (55. 56. a ala ale ale ale ale dy dt dy dx dy dt dy dx dy dt dy dx dy dx = x³, y(0) = 4 nodi.. = 2t +9t², y(1) = 2 = √t, y(1) = 1 = 8x³ + 3x², y(2) = 0 - (3x + 2)³, y(0) = 1 azi ONDE :sin x, y (7) not to = (4t+3)-2, y(1) = 0 sec² x, y dy 48. 1789,30 dt = (7) = = 2 52. dz dt = = 3 191 teag Be
Transcribed Image Text:antiderivative tives of each. In Exercises 45-46, we demonstrate that, in general, you of a product of functions by taking a prod 45. Show that G(x) = x²ex is not an antiderivative of H(x) = 2xe* - 2et is. 46. Show that G(x) = 3x² sinx is not an antideriv 6x cos x but H(x) = 6x sin x + 6 cos x is. In Exercises 47-60, solve the initial value problem. dy dx 47. 49. 50. 51. (53. 54. (55. 56. a ala ale ale ale ale dy dt dy dx dy dt dy dx dy dt dy dx dy dx = x³, y(0) = 4 nodi.. = 2t +9t², y(1) = 2 = √t, y(1) = 1 = 8x³ + 3x², y(2) = 0 - (3x + 2)³, y(0) = 1 azi ONDE :sin x, y (7) not to = (4t+3)-2, y(1) = 0 sec² x, y dy 48. 1789,30 dt = (7) = = 2 52. dz dt = = 3 191 teag Be
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