In Exercises 37-42, set up the iterated integral for evaluating ƒ ƒ(r, 0, z) r dz dr de over the given region D. 37. D is the right circular cylinder whose base is the circle r = 2 sin 0 in the xy-plane and whose top lies in the plane z = 4 — y. X Z z = 4-y r = 2 sin 0
In Exercises 37-42, set up the iterated integral for evaluating ƒ ƒ(r, 0, z) r dz dr de over the given region D. 37. D is the right circular cylinder whose base is the circle r = 2 sin 0 in the xy-plane and whose top lies in the plane z = 4 — y. X Z z = 4-y r = 2 sin 0
In Exercises 37-42, set up the iterated integral for evaluating ƒ ƒ(r, 0, z) r dz dr de over the given region D. 37. D is the right circular cylinder whose base is the circle r = 2 sin 0 in the xy-plane and whose top lies in the plane z = 4 — y. X Z z = 4-y r = 2 sin 0
Solution for integral with theta says it would be integral from 0 to pi but I don't understand how or why that would be.
Shouldn't it be from 0 to 2pi?
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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