In Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. 35. (x – 2) = 8(y – 1) 37. (x + 1) = -8(y + 1) 39. (y + 3) = 12(x + 1) 41. (y + 1) = -&r 36. (x + 2) = 4(y + 1) 38. (x + 2) = -8(y + 2) 40. (y + 4)2 = 12(x + 2) %3D %3D 42. (y - 1) = -&r
In Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. 35. (x – 2) = 8(y – 1) 37. (x + 1) = -8(y + 1) 39. (y + 3) = 12(x + 1) 41. (y + 1) = -&r 36. (x + 2) = 4(y + 1) 38. (x + 2) = -8(y + 2) 40. (y + 4)2 = 12(x + 2) %3D %3D 42. (y - 1) = -&r
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![In Exercises 35–42, find the vertex, focus, and directrix of each
parabola with the given equation. Then graph the parabola.
35. (x – 2) = 8(y – 1)
37. (x + 1) = -8(y + 1)
39. (y + 3) = 12(x + 1)
41. (y + 1) = -&r
36. (x + 2) = 4(y + 1)
38. (x + 2) = -8(y + 2)
40. (y + 4)2 = 12(x + 2)
%3D
%3D
42. (y - 1) = -&r](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d8b2af1-4d2a-49c0-8280-6d47de96245a%2F5069c85f-1cb5-42c3-8f1e-f053c12e4431%2Ffdycsas_processed.png&w=3840&q=75)
Transcribed Image Text:In Exercises 35–42, find the vertex, focus, and directrix of each
parabola with the given equation. Then graph the parabola.
35. (x – 2) = 8(y – 1)
37. (x + 1) = -8(y + 1)
39. (y + 3) = 12(x + 1)
41. (y + 1) = -&r
36. (x + 2) = 4(y + 1)
38. (x + 2) = -8(y + 2)
40. (y + 4)2 = 12(x + 2)
%3D
%3D
42. (y - 1) = -&r
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