In exercises 33-36, use the Intermediate Value Theorem to ver- ify that f(x) has a zero in the given interval. Then use the method of bisections to find an interval of length 1/32 that contains the zero. 33. f(x) = x² – 7, (a) [2, 3]: (b) [-3, -2]
In exercises 33-36, use the Intermediate Value Theorem to ver- ify that f(x) has a zero in the given interval. Then use the method of bisections to find an interval of length 1/32 that contains the zero. 33. f(x) = x² – 7, (a) [2, 3]: (b) [-3, -2]
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![In exercises 33-36, use the Intermediate Value Theorem to ver-
ify that f(x) has a zero in the given interval. Then use the method
of bisections to find an interval of length 1/32 that contains the
zero.
33. f(x) = x² – 7.
(a) [2, 3]:
(b) [-3, -2]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F02740986-c7a5-4ceb-b6ec-f44b51dd8ed7%2F66718d56-3a5f-459d-b572-ca05f5b81d11%2F2fmotfm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In exercises 33-36, use the Intermediate Value Theorem to ver-
ify that f(x) has a zero in the given interval. Then use the method
of bisections to find an interval of length 1/32 that contains the
zero.
33. f(x) = x² – 7.
(a) [2, 3]:
(b) [-3, -2]
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