In Exercises 29-32, (a) does the equation Ax = 0 have a nontriv- ial solution and (b) does the equation Ax = b have at least one solution for every possible b? 29. A is a 3 x 3 matrix with three pivot positions.
In Exercises 29-32, (a) does the equation Ax = 0 have a nontriv- ial solution and (b) does the equation Ax = b have at least one solution for every possible b? 29. A is a 3 x 3 matrix with three pivot positions.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
29
![0
0
e
fy
its
ar-
Ax = b, and define v = w- p. Show that v, is a solution
of Ax = 0. This shows that every solution of Ax = b has the
form w=p+Vh, with p a particular solution of Ax = b and
Vh a solution of Ax = 0.
26. Suppose Ax = b has a solution. Explain why the solution is
unique precisely when Ax = 0 has only the trivial solution.
27. Suppose A is the 3 x 3 zero matrix (with all zero entries).
Describe the solution set of the equation Ax = 0.
28. If b 0, can the solution set of Ax = b be a plane through
the origin? Explain.d
In Exercises 29-32, (a) does the equation Ax = 0 have a nontriv-
ial solution and (b) does the equation Ax = b have at least one
solution for every possible b?
29. A is a 3 x 3 matrix with three pivot positions.
30. A is a 3 x 3 matrix with two pivot positions.
31. A is a 3 x 2 matrix with two pivot positions.
32. A is a 2 x 4 matrix with two pivot positions.
-6
33. Given A=
os noi
-2
7
-3
quam
15
COPE
21 find one nontrivial solution of
-9
15tted bas
1
2 -1
35. Cons
1
36. Cons
1
-2
1
moth
14
4 -5
-1 8
37. Cons
38. Supp
2MB the e
exist
uniqu
with
Ax = 0 by inspection. [Hint: Think of the equation Ax = 0 B A(u
written as a vector equation.]
A(cu
15geris tui mi
equa
origi
o of A:
Ax =
39.
Let A
fies t
tor cu
40. Let
SOLUTIONS TO PRACTICE PRO
1. Row reduce the augmented matri
srl bol
0
8]-[
9](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F44c16932-10bc-4451-b37a-e5aaef6c0537%2F93c10ce0-7707-449c-81f8-eb0df5e59b24%2Fdw8t03l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:0
0
e
fy
its
ar-
Ax = b, and define v = w- p. Show that v, is a solution
of Ax = 0. This shows that every solution of Ax = b has the
form w=p+Vh, with p a particular solution of Ax = b and
Vh a solution of Ax = 0.
26. Suppose Ax = b has a solution. Explain why the solution is
unique precisely when Ax = 0 has only the trivial solution.
27. Suppose A is the 3 x 3 zero matrix (with all zero entries).
Describe the solution set of the equation Ax = 0.
28. If b 0, can the solution set of Ax = b be a plane through
the origin? Explain.d
In Exercises 29-32, (a) does the equation Ax = 0 have a nontriv-
ial solution and (b) does the equation Ax = b have at least one
solution for every possible b?
29. A is a 3 x 3 matrix with three pivot positions.
30. A is a 3 x 3 matrix with two pivot positions.
31. A is a 3 x 2 matrix with two pivot positions.
32. A is a 2 x 4 matrix with two pivot positions.
-6
33. Given A=
os noi
-2
7
-3
quam
15
COPE
21 find one nontrivial solution of
-9
15tted bas
1
2 -1
35. Cons
1
36. Cons
1
-2
1
moth
14
4 -5
-1 8
37. Cons
38. Supp
2MB the e
exist
uniqu
with
Ax = 0 by inspection. [Hint: Think of the equation Ax = 0 B A(u
written as a vector equation.]
A(cu
15geris tui mi
equa
origi
o of A:
Ax =
39.
Let A
fies t
tor cu
40. Let
SOLUTIONS TO PRACTICE PRO
1. Row reduce the augmented matri
srl bol
0
8]-[
9
![0
0
e
fy
its
ar-
Ax = b, and define v = w- p. Show that v, is a solution
of Ax = 0. This shows that every solution of Ax = b has the
form w=p+Vh, with p a particular solution of Ax = b and
Vh a solution of Ax = 0.
26. Suppose Ax = b has a solution. Explain why the solution is
unique precisely when Ax = 0 has only the trivial solution.
27. Suppose A is the 3 x 3 zero matrix (with all zero entries).
Describe the solution set of the equation Ax = 0.
28. If b 0, can the solution set of Ax = b be a plane through
the origin? Explain.d
In Exercises 29-32, (a) does the equation Ax = 0 have a nontriv-
ial solution and (b) does the equation Ax = b have at least one
solution for every possible b?
29. A is a 3 x 3 matrix with three pivot positions.
30. A is a 3 x 3 matrix with two pivot positions.
31. A is a 3 x 2 matrix with two pivot positions.
32. A is a 2 x 4 matrix with two pivot positions.
-6
33. Given A=
os noi
-2
7
-3
quam
15
COPE
21 find one nontrivial solution of
-9
15tted bas
1
2 -1
35. Cons
1
36. Cons
1
-2
1
moth
14
4 -5
-1 8
37. Cons
38. Supp
2MB the e
exist
uniqu
with
Ax = 0 by inspection. [Hint: Think of the equation Ax = 0 B A(u
written as a vector equation.]
A(cu
15geris tui mi
equa
origi
o of A:
Ax =
39.
Let A
fies t
tor cu
40. Let
SOLUTIONS TO PRACTICE PRO
1. Row reduce the augmented matri
srl bol
0
8]-[
9](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F44c16932-10bc-4451-b37a-e5aaef6c0537%2F93c10ce0-7707-449c-81f8-eb0df5e59b24%2Frby4kwg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:0
0
e
fy
its
ar-
Ax = b, and define v = w- p. Show that v, is a solution
of Ax = 0. This shows that every solution of Ax = b has the
form w=p+Vh, with p a particular solution of Ax = b and
Vh a solution of Ax = 0.
26. Suppose Ax = b has a solution. Explain why the solution is
unique precisely when Ax = 0 has only the trivial solution.
27. Suppose A is the 3 x 3 zero matrix (with all zero entries).
Describe the solution set of the equation Ax = 0.
28. If b 0, can the solution set of Ax = b be a plane through
the origin? Explain.d
In Exercises 29-32, (a) does the equation Ax = 0 have a nontriv-
ial solution and (b) does the equation Ax = b have at least one
solution for every possible b?
29. A is a 3 x 3 matrix with three pivot positions.
30. A is a 3 x 3 matrix with two pivot positions.
31. A is a 3 x 2 matrix with two pivot positions.
32. A is a 2 x 4 matrix with two pivot positions.
-6
33. Given A=
os noi
-2
7
-3
quam
15
COPE
21 find one nontrivial solution of
-9
15tted bas
1
2 -1
35. Cons
1
36. Cons
1
-2
1
moth
14
4 -5
-1 8
37. Cons
38. Supp
2MB the e
exist
uniqu
with
Ax = 0 by inspection. [Hint: Think of the equation Ax = 0 B A(u
written as a vector equation.]
A(cu
15geris tui mi
equa
origi
o of A:
Ax =
39.
Let A
fies t
tor cu
40. Let
SOLUTIONS TO PRACTICE PRO
1. Row reduce the augmented matri
srl bol
0
8]-[
9
Expert Solution

Step 1
Introduction:
Pivots in a matrix;
- Any row that does not contain only zeros its first non zero number is a 1 also is called the leading 1. These are also called pivots.
- For two successive rows with leading 1's, the 1 in the lower row is to the right of the 1 in the upper row.
Given: A is a matrix with three pivot positions.
To find:
Justify the solutions for the system.
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