In exercises 27–30, use the position function to find the velocity at time t = to. Assume units of feet and seconds. 27. s(t) = t² – sin 2t, to = 0 28. s(t) = 4+ 3 sin t , to = IT cos t 29. s(t) = to = JT 30. s(t) = t cos(t2 +1), to = 0
In exercises 27–30, use the position function to find the velocity at time t = to. Assume units of feet and seconds. 27. s(t) = t² – sin 2t, to = 0 28. s(t) = 4+ 3 sin t , to = IT cos t 29. s(t) = to = JT 30. s(t) = t cos(t2 +1), to = 0
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please answer the highlighted question with steps, lesson name is (derivatives of trigonometric functions)

Transcribed Image Text:In exercises 27–30, use the position function to find the velocity
at time t = to. Assume units of feet and seconds.
27. s(t) = t² –- sin 2t , to = 0
28. s(t) = 4+3 sin t , to = T
cos t
29. s(t) =
, to = T
30. s(t) = t cos(t² + r ), to = 0

Transcribed Image Text:3. f(t) = tan³ 2t – csc+ 3t
4. f(t) = t² + 2 cos² 4t
5. f(x)
= x cos 5.xr?
6. f(x)= x² sec 4x
x²
8. f(x)=
sin x?
7. f(x)=
x2
csc+ 2.x
9. f(t) = sin 3t sec 3t
10. f(t) = vcos 5t sec 5t
1
11. f(w) =
12. f(w) = w² sec² 3w
sin 4w
13. f(x) = 2 sin 2x cos 2x
14. f(x)= 4 sin? 3x + 4 cos² 3x
15. f(x) = tan Vx2 + 1
16. f(x)= 4x² sin x sec 3x
(cos /
17. f(x) =
sin³
cos Vx3 + 2x²
18. f(x)= tan“(sin (x³ + 2x))
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