In Exercises 139–142, determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. x2 – 25 = x - 5 5 139. X - x? + 7 140. = x? + 1 7 7 domain of f(x) = is x(x – 3) + 5(x - 3) 141. The (-0, 3) U (3, 0). 142. The restrictions on the values of x when performing the division f(x) h(x) g(x) k (x) are g(x) + 0, k(x) # 0, and h(x) + 0.
In Exercises 139–142, determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. x2 – 25 = x - 5 5 139. X - x? + 7 140. = x? + 1 7 7 domain of f(x) = is x(x – 3) + 5(x - 3) 141. The (-0, 3) U (3, 0). 142. The restrictions on the values of x when performing the division f(x) h(x) g(x) k (x) are g(x) + 0, k(x) # 0, and h(x) + 0.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 7RE
Related questions
Question
![In Exercises 139–142, determine whether each statement is true
or false. If the statement is false, make the necessary change(s)
to produce a true statement.
x2 – 25
= x - 5
5
139.
X -
x? + 7
140.
= x? + 1
7
7
domain
of
f(x) =
is
x(x – 3) + 5(x - 3)
141. The
(-0, 3) U (3, 0).
142. The restrictions on the values of x when performing the
division
f(x)
h(x)
g(x)
k (x)
are g(x) + 0, k(x) # 0, and h(x) + 0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fdfcde4-0e66-4ae7-bb40-55ac79eacdfe%2Fb898c87d-a659-45cb-8e85-2c6e135d2b95%2Fpr2sg68_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In Exercises 139–142, determine whether each statement is true
or false. If the statement is false, make the necessary change(s)
to produce a true statement.
x2 – 25
= x - 5
5
139.
X -
x? + 7
140.
= x? + 1
7
7
domain
of
f(x) =
is
x(x – 3) + 5(x - 3)
141. The
(-0, 3) U (3, 0).
142. The restrictions on the values of x when performing the
division
f(x)
h(x)
g(x)
k (x)
are g(x) + 0, k(x) # 0, and h(x) + 0.
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