In Exercises 13–18, calculate the derivative in two ways. First use the Product or Quotient Rule; then rewrite the function algebraically and directly calculate the derivative. h(x) = %3D

Q: nd f(/x)=5g(x)+1 %3D

A: The given function is ,  fx=3x+2  ......................1  fx=5gx+1   ....................2 To…

Q: C. f [x) = ler -x %31

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Q: Solve y + 4y = e4* y(0) = 2 %3D

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Q: XL - Eλ = (x)6 ^ = (x),6

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Q: f(x)= -2x2 + 3 from x = 2 to x = 5 Average rate of change =

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Q: If f(x) rate of change of f(x) at x = 3x + 7x + 7, find the instantaneous – 2. - - Answer = %3D

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Q: Using the function g (x) = 2x + 5x + 6, fill in the blank. The instantaneous rate of change of g (x)…

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Q: Find the second derivative of the function. . f(x) = 4x3/2 : 1. g(x) = %3D X-1 .. h(x) = secx

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Q: Determine the value(s) of x where the slope of the tangent to g(x) = (x+ 5)(x² – 1) is -7. %3D

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Q: r(x) = 4 ln(1.2)(1.2x); r(x) = 9.6, r(x) = 25 r(x) = 9.6     x  =        r(x) = 25     x  =

A: Given r(x)=9.6, we have to find x for that. First we plug r(x)=9.6 in the equation.