In Exercises 125-134, solve each equation. 125. 25 - [2 + 5x – 3(x + 2)] = -3(2x – 5) – [5(x – 1) – 3x + 3] 126. 45 - [4 - 2x – 4(x + 7)] = -4(1 + 3x) – [4 – 3(x + 2) – 2(2x – 5)] 127. 7 - 7x = (3x + 2)(x - 1) 128. 10x - 1 = (2r + 1) 129. |x + 2x – 36| = 12 130. |x + 6x + 1| = 8 1 + 1 5 131. 3x + 2 x + 2 x? - 4 1 132. X - 2 X - 3 x - 5x + 6 133. Vx + 8 - Vx 4 = 2 134. Vx + 5 – Vx - 3 = 2 + 1.
In Exercises 125-134, solve each equation. 125. 25 - [2 + 5x – 3(x + 2)] = -3(2x – 5) – [5(x – 1) – 3x + 3] 126. 45 - [4 - 2x – 4(x + 7)] = -4(1 + 3x) – [4 – 3(x + 2) – 2(2x – 5)] 127. 7 - 7x = (3x + 2)(x - 1) 128. 10x - 1 = (2r + 1) 129. |x + 2x – 36| = 12 130. |x + 6x + 1| = 8 1 + 1 5 131. 3x + 2 x + 2 x? - 4 1 132. X - 2 X - 3 x - 5x + 6 133. Vx + 8 - Vx 4 = 2 134. Vx + 5 – Vx - 3 = 2 + 1.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![In Exercises 125-134, solve each equation.
125. 25 - [2 + 5x – 3(x + 2)] =
-3(2x – 5) – [5(x – 1) – 3x + 3]
126. 45 - [4 - 2x – 4(x + 7)] =
-4(1 + 3x) – [4 – 3(x + 2) – 2(2x – 5)]
127. 7 - 7x = (3x + 2)(x - 1)
128. 10x - 1 = (2r + 1)
129. |x + 2x – 36| = 12
130. |x + 6x + 1| = 8
1
+
1
5
131.
3x + 2
x + 2
x? - 4
1
132.
X - 2
X - 3
x - 5x + 6
133. Vx + 8 -
Vx
4 = 2
134. Vx + 5 – Vx - 3 = 2
+
1.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9e510f99-2a5a-4ea8-9f4b-41bac4bc1dfd%2Fd4016238-6804-48f1-bd25-6ebae273714a%2Fc361n89_processed.png&w=3840&q=75)
Transcribed Image Text:In Exercises 125-134, solve each equation.
125. 25 - [2 + 5x – 3(x + 2)] =
-3(2x – 5) – [5(x – 1) – 3x + 3]
126. 45 - [4 - 2x – 4(x + 7)] =
-4(1 + 3x) – [4 – 3(x + 2) – 2(2x – 5)]
127. 7 - 7x = (3x + 2)(x - 1)
128. 10x - 1 = (2r + 1)
129. |x + 2x – 36| = 12
130. |x + 6x + 1| = 8
1
+
1
5
131.
3x + 2
x + 2
x? - 4
1
132.
X - 2
X - 3
x - 5x + 6
133. Vx + 8 -
Vx
4 = 2
134. Vx + 5 – Vx - 3 = 2
+
1.
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