In exercises 1-10, classify each of the following integral equations as Fredholm or Volterra integral equation, linear or nonlinear, and homogeneous or nonhomogeneous: (1) u(x) = x+ (2) u(x) = 1 + x² + (3) u(x) = dt fatu(t) d S² (₂ = et + (4) u(x) = [²(x - 1)² u(t) dt 2 (5) u(2) = 2 + [atu (7) u(x) = 1 + (x - t)u(t) dt tu² (t) dt x 3 1 (6) u(z) = 2 + + √(x-1)³ u(t) dt 5 1 1 x+tu(t) xtu(t) dt dt
In exercises 1-10, classify each of the following integral equations as Fredholm or Volterra integral equation, linear or nonlinear, and homogeneous or nonhomogeneous: (1) u(x) = x+ (2) u(x) = 1 + x² + (3) u(x) = dt fatu(t) d S² (₂ = et + (4) u(x) = [²(x - 1)² u(t) dt 2 (5) u(2) = 2 + [atu (7) u(x) = 1 + (x - t)u(t) dt tu² (t) dt x 3 1 (6) u(z) = 2 + + √(x-1)³ u(t) dt 5 1 1 x+tu(t) xtu(t) dt dt
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![In exercises 1-10, classify each of the following integral equations as Fredholm or
Volterra integral equation, linear or nonlinear, and homogeneous or nonhomogeneous:
(1) u(x) = x +
(2) u(x) = 1 + x² + √(x − t)u(t) dt
-
(3) u(x) = e² + ² tu²³ (t) dt
3
(6) u(x) = ²
So
(4) u(x) = f (x - t)² u(t) dt
(5) u(x) = ²/2 + (¹xtu(t) dt
(7) u(x) = 1 +
xtu(t) dt
(10) u(x) =
1
x+ 5+
x
3 6
(x-1)³ u(t) dt
1
= 1-
1
x+tu(t)
/0
(8) u(x) = = = cos x + ²/2 √² cos x u(t) dt
[²* (x − 1)² u² (1) dt
(9) u(x) = 1 +
10
dt
- 5²(x - t)u(t) dt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F17a2fc5a-fa96-4a6f-a39e-0cd2847315b8%2Fc4f8fa6b-6f91-4ca7-8d2b-e532c2f019d3%2Fo208sgm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In exercises 1-10, classify each of the following integral equations as Fredholm or
Volterra integral equation, linear or nonlinear, and homogeneous or nonhomogeneous:
(1) u(x) = x +
(2) u(x) = 1 + x² + √(x − t)u(t) dt
-
(3) u(x) = e² + ² tu²³ (t) dt
3
(6) u(x) = ²
So
(4) u(x) = f (x - t)² u(t) dt
(5) u(x) = ²/2 + (¹xtu(t) dt
(7) u(x) = 1 +
xtu(t) dt
(10) u(x) =
1
x+ 5+
x
3 6
(x-1)³ u(t) dt
1
= 1-
1
x+tu(t)
/0
(8) u(x) = = = cos x + ²/2 √² cos x u(t) dt
[²* (x − 1)² u² (1) dt
(9) u(x) = 1 +
10
dt
- 5²(x - t)u(t) dt
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