In executing the following code: MOV CX, 0002 START: MOV SI, 0300 MOV DI, 0302 LOOP: XOR (DI), AL INC SI MOVAL, (SI) INC DI DEC CX JNZ LOOP HLT with the following byte contents: (0300H) = 0AH, (0301H) = OBH, (0302H) = 11H, (0303H) = 21H. The result will be: Select one: O a. (0300H) = OAH, (0301H) = OBH, (0302H) = 1AH, (0303H) = 2BH (0300H) = 0AH, (0301H) = OBH, (0302H) = 10H, (0303H) = 20H O b. O c. (0300H) = OAH, (0301H) = 0BH, (0302H) = 1AH, (0303H) = 20H d. None of the options given here e. (0300H) = 0AH, (0301H) = OBH, (0302H) = 1BH, (0303H) = 2AH

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