in effect, any partial sum of the series is a suitable Taylor polynomial of the function f(x) at zero. The formula (2.1) is often used to approximate the values of the natural logarithm. Say, setting x = 1/3, we obtain from (2.1) the infinite series representing In(2), due to 1+1/3 1-1/3 = 2. (i) Find a rational number x = p/q which is the solution of the equation

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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(Taylor Series/Polynomials, Natural Logarithm). All numerical answers, unless otherwise required, should be rounded to 6-
digit floating-point numbers.
(0) It is known that
for all x € (-1, 1).
x =
and enter it (in reduced form) in the input field below:
In fact, the series in the right-hand side is the Taylor series at zero of the function
x²k+1\
x
In 1+3 = 2 (2 32++1)
1-x
k=U
in effect, any partial sum of the series is a suitable Taylor polynomial of the function f(x) at zero.
The formula (2.1) is often used to approximate the values of the natural logarithm. Say, setting x = 1/3, we obtain from
(2.1) the infinite series representing In(2), due to
1 + 1/3
1-1/3
(i) Find a rational number x = p/q which is the solution of the equation
1 + x
1-x
Find an approximation y* of y = In(1.38)
*
f(x) = In
RE(y y*) =
1+x
SD(y = y*) =
- X
We then have In(1.38) is equal to the sum of the series in (2.1) for x = p/q.
(ii) Consider the first five terms of the series in (2.1), that is, the ninth Taylor polynomial of the function f(x) at zero,
as
= 2.
= 1.38
TX) = 2(x + = + = + = + =)
T(x)
* = T(p/q),
where p/q is the rational number you have found in (i), and enter your result, rounded to a 6-digit floating-number, in the
input field below:
(iii) Find the absolute, the relative error, and the number of significant digits in the approximation of y = ln(1.38)
AE(y y*) =
(2.1)
by y* :
Transcribed Image Text:(Taylor Series/Polynomials, Natural Logarithm). All numerical answers, unless otherwise required, should be rounded to 6- digit floating-point numbers. (0) It is known that for all x € (-1, 1). x = and enter it (in reduced form) in the input field below: In fact, the series in the right-hand side is the Taylor series at zero of the function x²k+1\ x In 1+3 = 2 (2 32++1) 1-x k=U in effect, any partial sum of the series is a suitable Taylor polynomial of the function f(x) at zero. The formula (2.1) is often used to approximate the values of the natural logarithm. Say, setting x = 1/3, we obtain from (2.1) the infinite series representing In(2), due to 1 + 1/3 1-1/3 (i) Find a rational number x = p/q which is the solution of the equation 1 + x 1-x Find an approximation y* of y = In(1.38) * f(x) = In RE(y y*) = 1+x SD(y = y*) = - X We then have In(1.38) is equal to the sum of the series in (2.1) for x = p/q. (ii) Consider the first five terms of the series in (2.1), that is, the ninth Taylor polynomial of the function f(x) at zero, as = 2. = 1.38 TX) = 2(x + = + = + = + =) T(x) * = T(p/q), where p/q is the rational number you have found in (i), and enter your result, rounded to a 6-digit floating-number, in the input field below: (iii) Find the absolute, the relative error, and the number of significant digits in the approximation of y = ln(1.38) AE(y y*) = (2.1) by y* :
and enter it (in reduced form) in the input field below:
X =
We then have In(1.38) is
(ii) Consider the first fiv
Find an approximation y* of y = In(1.38) as
=
T(x) = 2 ( x + ² + ² + ² + )
3
5
7
9
y* = T(p/q),
where p/q is the rational number you have found in (i), and enter your result, rounded to a 6-digit floating-number, in the
input field below:
RE(y≈ y*) =
ion f(x) at zero,
(iii) Find the absolute, the relative error, and the number of significant digits in the approximation of y = In(1.38) by y*:
AE(y = y*) =
SD(y = y) =
Transcribed Image Text:and enter it (in reduced form) in the input field below: X = We then have In(1.38) is (ii) Consider the first fiv Find an approximation y* of y = In(1.38) as = T(x) = 2 ( x + ² + ² + ² + ) 3 5 7 9 y* = T(p/q), where p/q is the rational number you have found in (i), and enter your result, rounded to a 6-digit floating-number, in the input field below: RE(y≈ y*) = ion f(x) at zero, (iii) Find the absolute, the relative error, and the number of significant digits in the approximation of y = In(1.38) by y*: AE(y = y*) = SD(y = y) =
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