In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has 245 loops, is 2.51 V. The emf induced in coil 2 is 4.90 V. How many loops does coil 2 have? Number i Units
The emf induced in a coil is given by the equation: emf = -N(dΦ/dt) where N is the number of turns in the coil, Φ is the magnetic flux through a single turn of the coil, and dΦ/dt is the rate of change of the magnetic flux.
We can rearrange this equation to solve for the number of turns in coil 2: N2 = (emf2/(-dΦ/dt))
We are given that the rate of change of the magnetic flux is the same for both coils. Therefore, we can use the emf and number of turns for coil 1 to find the rate of change of the magnetic flux: dΦ/dt = -emf1/N1
Substituting the values given, we get: dΦ/dt = -(2.51 V)/(245 turns)
Now we can use this value to solve for the number of turns in coil 2: N2 = (4.90 V)/[(2.51 V)/(245 turns)] N2 = 480 turns
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
