In each of Problem 9 through 24, use the linearity of L¹, partial fraction expression, and Table 5.3.1 to find the inverse Laplace transform of the given function: 23- -28²-68-6 (s²+2s+2) s²
In each of Problem 9 through 24, use the linearity of L¹, partial fraction expression, and Table 5.3.1 to find the inverse Laplace transform of the given function: 23- -28²-68-6 (s²+2s+2) s²
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:In each of Problem 9 through 24, use the linearity of L¹, partial fraction expression, and Table 5.3.1 to find the
inverse Laplace transform of the given function:
23.
-28²-68-6
(s²+2s+2)s²

Transcribed Image Text:1.
2.
f(t) = -¹{F(s)}
1
eat
t", n = positive integer
3.
4. t,p>-1
5. sin at
6.
cos at
sinh at
7.
8. cosh at
9. et sin bt
10. et cos bt
11. teat, n positive integer
12. uc(t)
13. uc(t)f(t-c)
14. e f(t)
15. ff(t-1) 9(7) dr
16. (t-c)
17. f(n) (t)
18 the f(t)
F(s) = L{f(t)}
1,8>0
s>a
g+18>0
r(p+1)
8> 0
8>0
8>0
8> lal
8> |a|
(5-4)² +52) > a
8
(5-4)² +6²
8>a
+
+
s> a
(s-a) **I'
e, s>0
e-cs F(s)
F(s-c)
F(s)G(s)
s" F(s)-8"-1f(0) -
(-1)^ f(n) (s)
- f(n-1) (0)
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