In each figure below, a system consisting of two blocks that are tied together is attached to a spring. Thesystems are all at rest, and all of the springs are stretched by the same amount. The blocks on thehorizontal surface are all identical, but the masses of the blocks on the inclined surfaces and the springconstants of the springs vary as shown in the figures. There may be friction between the blocks and thesurfaces.ABC4 kgk = 120 N/m7kgk = 150 N/m5 kgk = 120 N/mDEFk = 150 N/m5 kgk = 180 N/mk = 150 N/m4 kg5 kgRank these cases on the basis of the spring potential energy._2.Greatest1345LeastOR, The spring potential energy is the same for all these systems, but it is not zero.OR, The spring potential energy is zero for all these systems.OR, We cannot determine the ranking for the spring potential energy.Please explain your reasoning.

Answered: Image /qna-images/answer/b0323232-5674-4a44-895f-cd3691011f13.jpg

In each figure below, a system consisting of two blocks that are tied together is attached to a spring. The systems are all at rest, and all of the springs are stretched by the same amount. The blocks on the horizontal surface are all identical, but the masses of the blocks on the inclined surfaces and the spring constants of the springs vary as shown in the figures. There may be friction between the blocks and the surfaces. A 4 kg k = 120 N/m kg k = 150 N/m 5 kg k = 120 N/m E www k = 180 N/m 4 kg k = 150 N/m 5kg k = 150 N/m 5 kg Rank these cases on the basis of the spring potential energy. Greatest .2 3 .5 Least

In each figure below, a system consisting of two blocks that are tied together is attached to a spring. The systems are all at rest, and all of the springs are stretched by the same amount. The blocks on the horizontal surface are all identical, but the masses of the blocks on the inclined surfaces and the spring constants of the springs vary as shown in the figures. There may be friction between the blocks and the surfaces. A 4 kg k = 120 N/m kg k = 150 N/m 5 kg k = 120 N/m E www k = 180 N/m 4 kg k = 150 N/m 5kg k = 150 N/m 5 kg Rank these cases on the basis of the spring potential energy. Greatest .2 3 .5 Least

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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