In each case, determine whether or not the lines have a single point of intersection. If they do, give an equation of a plane containing them. a) r₁ = (5t, 2t 1,3t 3) and r₂ = (t−6, -t + 5, t - 9)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In each case, determine whether or not the lines have a single point of intersection. If they do, give an equation of a plane
containing them.
a) r₁
=
(5t, 2t - 1, 3t 3) and r₂ = (t -6, -t + 5,t - 9)
b) r₁ =
(4t, −4t + 1, t − 5) and r₂ = (2t — 3, −t, −t − 1)
(Express numbers in exact form. Use symbolic notation and fractions where needed. Enter DNE if lines do not intersect.)
(a) the equation of the plane:
(b) the equation of the plane:
Transcribed Image Text:In each case, determine whether or not the lines have a single point of intersection. If they do, give an equation of a plane containing them. a) r₁ = (5t, 2t - 1, 3t 3) and r₂ = (t -6, -t + 5,t - 9) b) r₁ = (4t, −4t + 1, t − 5) and r₂ = (2t — 3, −t, −t − 1) (Express numbers in exact form. Use symbolic notation and fractions where needed. Enter DNE if lines do not intersect.) (a) the equation of the plane: (b) the equation of the plane:
Expert Solution
Step 1

a Given that r1=5t,2t1,3t3 and r2=t6,t+5,t9.

We have to find the equation of the plane.

Now, r1 at t1=5t1,2t11,3t13

And r2 at t2=t26,t2+5,t29

For intersection point

5t1=t26........12t11=t2+5......23t13=t29........3

Now, solve equation 1, 2 and 3, we get

t1=0 and t2=6

If we substitute t1=0 and t2=6 in equation 3, it satisfy the third equation.

Hence, r1 and r2 intersects each other.

Now at t1=0, r1=0,1,3.

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