In developing an interval estimate for a populationmean, a sample of 50 observations was used. Theinterval estimate was 19.76 ± 1.32. Had the samplesize been 200 instead of 50, the interval estimatewould have beenA. 9.88 ± 1.32В. 19.76 + 0.66С. 4.94 + 1.32D. 19.76 ± 0.33The minimum sample size needed to estimate apopulation mean within 2 units with a 95% confidencewhen the population standard deviation equals 8 isA. 9В. 8С. 61D. 62

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Description: In developing an interval estimate for a populationmean, a sample of 50 observations was used. Theinterval estimate was 19.76 ± 1.32. Had the samplesize been 200 instead of 50, the interval estimatewould have beenA. 9.88 ± 1.32В. 19.76 + 0.66С. 4.94

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In developing an interval estimate for a population mean, a sample of 50 observations was used. The interval estimate was 19.76 + 1.32. Had the sample size been 200 instead of 50, the interval estimate would have been A. 9.88 ± 1.32 B. 19.76 ± 0.66 C. 4.94 ± 1.32 D. 19.76 + 0.33

In developing an interval estimate for a population mean, a sample of 50 observations was used. The interval estimate was 19.76 + 1.32. Had the sample size been 200 instead of 50, the interval estimate would have been A. 9.88 ± 1.32 B. 19.76 ± 0.66 C. 4.94 ± 1.32 D. 19.76 + 0.33

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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