in december 2001 the research firm gfk surveyed baby boomers (americans born between 1946 and 1964) gfk contacted 1006 randomly selected baby boomers by cell phone or land-line. thee vas majority, 71% reported that they have provided support to their adult children in the form of helping them pay for college tuition or loans. what is the sample proportion? estimate the standard error. round to the thousandths place  findd the margin error for a 90% confidence interval. round to the thousandths place

Q: In a survey, 8 people were asked how much they spent on their child's last birthday gift. The…

A: The sample size, i.e., the sampled number of people, n=8.The sample mean, x¯=$37.The sample standard…

Q: What is the role of the sample size in the determination of confidence interval? Explain.

A: Let us first define sample size and confidence interval. Sample size: It is determination of the…

Q: What is the formula for the 95% confidence interval for a population mean, given a sample mean and…

A: Given that 95% confidence interval for populations mean.

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: a. How many of the 3039 subjects used at least one prescription medication? (Round to the nearest…

A: Given : Total sample size of the survey  = 3039 Out of the sample, proportion of people who have…

Q: Use the confidence interval to find the margin area (.596,.740)   margin of error?  samplemean?

A: Given confidence interval is (.596,.740) margin of error=? sample mean=?

Q: How do I calculate a 95% confidence level for a sample proportion in excel? Meaning, what formula…

A: Given : Confidence level = CL = 95% = 0.95

Q: Anystate Auto Insurance Company took a random sample of 378 insurance claims paid out during a…

A: given data  n = 378 x¯ = 1550σ = 264 find 90% ci for μ.

Q: Explain which would result in a wider large-sample confidence interval for : a 90%pconfidence level…

A: The z critical value for 95% confidence interval is 1.96 and the z-critical value for 90% confidence…

Q: A sample of size 50 from a normal distribution has sample mean 5 and sample variance 20. Find 96%…

A: To find the confidence interval for the variance, we need to use the Chi-squared distribution. The…

Q: What is the likelihood that a 90% confidence interval will not cover the true population value?…

A:

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: In a survey of 2405 adults in a recent​ year, 1217 say they have made a New Year's resolution.…

A: Given: n=2405 x=1217

Q: How does the sample size and percentage of confidence influence the width of a confidence interval?

A: We have to define effect on width of C.I.

Q: Find a 0.90 confidence interval for the mean claim payment. (Round your answers to two decimal…

A: Given that X bar = 1565; sigma = 264; n=376 We need to find the 90% confidence interval for the mean…

Q: Find the critics value Za/2 that corresponds to the give

A: Given confidence level is 91% That is,  1-a=91%1-a=0.911-0.91=a      0.09=a      0.092=a2…

Q: In a survey of 2407 adults in a recent​ year,1468 say they have made a New​ Year's resolution.…

A: Given that,  Sample size, n= 2407 And X= 1468 We know that proportion, p=X/n So p= 1468/2407 p=…

Q: Find the population proportion? find the margin of e? construct confidence interval ?

A:

Q: What's the below are the amount of net worth (in millions of dollars) of the 10 wealthiest…

A:

Q: Help In a survey of 3031 adults aged 57 through 85 years, it was found that 85.7% of them used at…

A: Given: n=3031 pcap=0.857

Q: The annual earnings (in dollars) of 35 randomly selected microbiologists are shown in the data…

A: From the provided information, Sample size (n) = 35 Confidence level = 98%

Q: In a survey of 2969 ​adults, 1401 say they have started paying bills online in the last year.…

A:

Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…

A: We have given data,  Less attendance Full attendance 90 96 90 96 60 100 50 99 69   88…

Q: tis A poll found that people from the north now have relatively warm feelings toward people from the…

A:

Q: igh school soccer league there are a total of 256 players.

A: Given that Total players in high school soccer league (n) = 256 players The mean height of the…

Q: A poll asked whether states should be allowed to conduct random drug tests on elected officials. Of…

A:

Q: help please answer in text form with proper workings and explanation for each and every part and…

A: Step 1 Step 2 Step 3 : Step 4

Q: A poll asked whether states should be allowed to conduct random drug tests on elected officials. Of…

A: n = 21410 p^ = 0.72 99% ci for p

Q: A newspaper provided a "snapshot" illustrating poll results from 1910 professionals who interview…

A: We have given that point estimate = 0.26Margin of error = ±3% 0.03 Sample size (n) = 1910

Q: Stanford University conducted a study of whether running is healthy for men and women over age 50.…

A: Given information: n = 695 P(Died) = 1.1%

Q: A packet of garden seeds contains 250 seeds. The information printed on the packet indicates that…

A: Given , n = 250

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: A research institute poll asked respondents if they acted to annoy a bad driver. In the poll, n=2320…

A: The random variable percentage of people who said they honked follows binomial distribution. The…

Q: Explain how to find the 95% confidence interval for the mean by hand using the following data set…

A: For the given sample, x¯=59.05, from the excel function, =AVERAGE(J2:J21)s=4.6394, from the excel…

Q: In a survey, 31 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey of 2417 adults in a recent​ year, 1458 say they have made a New​ Year's resolution.…

A:

Q: calculate the standard deviation for 3 plants

A:

Q: In a survey of 2497 adults in a recent​ year, 1383 say they have made a New​ Year's resolution.…

A: The sample size (n) is 2497 and the value of x is 1383.

Q: Pew Research Center poll of 1501 randomly selected U.S. adults showed that 70% of the respondents…

A:

Q: In a survey of 2554 adults in a recent​ year, 1357 say they have made a New​ Year's resolution.…

A:

Q: A psychologist asked a random sample to complete a depression questionnaire. On average, children…

A: We assume the population is normally distributed.

Q: What is the best estimate for the standard error of the sampling

A: Given data,Tota no of students n=14795Who said yes for cyberbullied is x=2219Point estimate is…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.