In computing for the mean in letter (c), we used ry = 3, in the formula because we let Y be the number of cameras tested to obtain third failure. If so, increasing the number of failed cameras also increases the expected number of cameras tested.

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b. P(X²4) = P/X=2) + P(X + 3) + P(x+4)
* Exal:
O True
False
E
0.0604
4.2
- (²) 0·20 ² (3-0.20) ² ² + (²) 0.20² (1-0.20)^² + (²) 1·20² (1-0-20) * · *
0.04 + 0.064 + 0.0768
0-1808
c. 9. # of cameras tasted until three failures, p= 0.20 14 = 3 =
E (4)
15 cameras
NEGBINOM. DIST (0₁2, 0.20, FALSE) + NYGBINOM. DIST (1, 2, 0.20, FALSE)
+ NEGBINDM. DIST7 (2,2,0.20, FALSE)
ru
ри
=
3
0.20
Transcribed Image Text:b. P(X²4) = P/X=2) + P(X + 3) + P(x+4) * Exal: O True False E 0.0604 4.2 - (²) 0·20 ² (3-0.20) ² ² + (²) 0.20² (1-0.20)^² + (²) 1·20² (1-0-20) * · * 0.04 + 0.064 + 0.0768 0-1808 c. 9. # of cameras tasted until three failures, p= 0.20 14 = 3 = E (4) 15 cameras NEGBINOM. DIST (0₁2, 0.20, FALSE) + NYGBINOM. DIST (1, 2, 0.20, FALSE) + NEGBINDM. DIST7 (2,2,0.20, FALSE) ru ри = 3 0.20
In computing for the mean in letter (c), we used ry = 3, in the formula because we let Y be the
number of cameras tested to obtain third failure. If so, increasing the number of failed cameras
also increases the expected number of cameras tested.
3-137. Consider the time to recharge the flash in cell-phone
cameras as in Example 3-2. Assume that the probability that
a camera passes the test is 0.8 and the cameras perform inde-
pendently. Determine the following:
(a) Probability that the second failure occurs on the tenth cam-
era tested.
(b) Probability that the second failure occurs in tests of four or
fewer cameras.
(B) Expected number of cameras tested to obtain the third
failure.
b. P(X²4) = P/X=2) + P(X+3) + P(x+4)
=
Example 3-2
The time to recharge the flash is tested in three cell-phone cameras. The probability that a camera
passes the test is 0.8, and the cameras perform independently. See Table 3-1 for the sample space
for the experiment and associated probabilities. For example, because the cameras are independent,
the probability that the first and second cameras pass the test and the third one fails, denoted as pis
PP) (0.80.80.2) = 0.128
=
The random variable X denotes the number of cameras that pass the test. The last column of the table shows the values
of X assigned to each outcome of the experiment
TABLE 3-1 Camera Flash Tests
Camera 2
Camera 1
Pass
Fal
Pass
Fal
Pass
Pass
22222222
Camera 3
let : X - # 7 cameras tested writil two foulures, p= 0.20 1.2
A. P(X= 10) = (2-1)
(2.1) 0-20² (1-0.20)10-2
0.0604
Pass
Pass
Fail
Fail
Fail
Probability
0.512
0.128
0.128
0.012
0.128
0.032
0.002
0.008
2
1
2
1
1
0
².2
4.2
(1) 0.20² (1-0.20) ²:² + (2) 0.20² (1.0.20) ^² + (²) 0.20² (1-0-20) 1.²
2
0.04 + 0.064 + 0.0768
0-1808
Transcribed Image Text:In computing for the mean in letter (c), we used ry = 3, in the formula because we let Y be the number of cameras tested to obtain third failure. If so, increasing the number of failed cameras also increases the expected number of cameras tested. 3-137. Consider the time to recharge the flash in cell-phone cameras as in Example 3-2. Assume that the probability that a camera passes the test is 0.8 and the cameras perform inde- pendently. Determine the following: (a) Probability that the second failure occurs on the tenth cam- era tested. (b) Probability that the second failure occurs in tests of four or fewer cameras. (B) Expected number of cameras tested to obtain the third failure. b. P(X²4) = P/X=2) + P(X+3) + P(x+4) = Example 3-2 The time to recharge the flash is tested in three cell-phone cameras. The probability that a camera passes the test is 0.8, and the cameras perform independently. See Table 3-1 for the sample space for the experiment and associated probabilities. For example, because the cameras are independent, the probability that the first and second cameras pass the test and the third one fails, denoted as pis PP) (0.80.80.2) = 0.128 = The random variable X denotes the number of cameras that pass the test. The last column of the table shows the values of X assigned to each outcome of the experiment TABLE 3-1 Camera Flash Tests Camera 2 Camera 1 Pass Fal Pass Fal Pass Pass 22222222 Camera 3 let : X - # 7 cameras tested writil two foulures, p= 0.20 1.2 A. P(X= 10) = (2-1) (2.1) 0-20² (1-0.20)10-2 0.0604 Pass Pass Fail Fail Fail Probability 0.512 0.128 0.128 0.012 0.128 0.032 0.002 0.008 2 1 2 1 1 0 ².2 4.2 (1) 0.20² (1-0.20) ²:² + (2) 0.20² (1.0.20) ^² + (²) 0.20² (1-0-20) 1.² 2 0.04 + 0.064 + 0.0768 0-1808
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