In computer graphics and perspective​ drawing, we need to represent objects seen by the eye in space as images on a​ two-dimensional plane. Suppose that the eye is at ​E(Xo​,0,0) as shown here and that we want to represent a point P(x1,y1,z1) as a point on the​ yz-plane. We do this by projecting P1 onto the plane with a ray from E. The point P1 will be portrayed as the point​ P(0,y,z). The problem for us as graphics designers is to find y and z given E and P1.  Write a vector equation that holds between vector EP and vector EP1. Use the equation to express y and z in terms of xo​, x1​, y1​, and z1. What is the correct vector​ equation? The magnitudes must be the​ same, EP = EP1 The cross product must be the zero​ vector, EP×EP1 = 0. The dot product must be​one, EP • EP1 = 1. The dot product must be​zero, EP • EP1 = 0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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In computer graphics and perspective​ drawing, we need to represent objects seen by the eye in space as images on a​ two-dimensional plane. Suppose that the eye is at ​E(Xo​,0,0) as shown here and that we want to represent a point P(x1,y1,z1) as a point on the​ yz-plane.

We do this by projecting P1 onto the plane with a ray from E. The point P1 will be portrayed as the point​ P(0,y,z). The problem for us as graphics designers is to find y and z given E and P1. 

Write a vector equation that holds between vector EP and vector EP1. Use the equation to express y and z in terms of xo​, x1​, y1​, and z1. What is the correct vector​ equation?

  • The magnitudes must be the​ same, EP = EP1
  • The cross product must be the zero​ vector, EP×EP1 = 0.
  • The dot product must be​one, EP • EP1 = 1.
  • The dot product must be​zero, EP • EP1 = 0

 

X
OL
Ex. 0,0)
P₁(x₁. 1. 21)
P(0, y, z)
(₁, 1, 0)
→y
Transcribed Image Text:X OL Ex. 0,0) P₁(x₁. 1. 21) P(0, y, z) (₁, 1, 0) →y
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