In circle S with MZRST = 42 and RS Round to the nearest hundredth. = 3 units, find the length of arc RT. %3D R

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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### Problem Statement

In circle \( S \) with \( m\angle RST = 42^\circ \) and \( RS = 3 \) units, find the length of arc \( RT \). Round to the nearest hundredth.

### Diagram
Below the problem statement, there is a diagram of a circle labeled \( S \) with points \( R \) and \( T \) on the circumference. Two line segments, \( RS \) and \( ST \), represent radii of the circle and are both 3 units long. The angle between these two radii, \( \angle RST \), is marked as \( 42^\circ \).

#### Circle Diagram Explanation
- Point \( S \) is the center of the circle.
- Point \( R \) is on the circumference of the circle.
- Point \( T \) is also on the circumference of the circle.
- Both \( RS \) and \( ST \) are radii of the circle with a length of 3 units.
- The angle \( \angle RST \) formed by the radii \( RS \) and \( ST \) is \( 42^\circ \).

### Solving the Problem
To find the length of arc \( RT \), you can use the following formula:

\[ \text{Length of Arc} = \left( \frac{\theta}{360} \right) \times 2\pi r \]

where:
- \( \theta \) is the central angle in degrees (in this case, \( 42^\circ \)).
- \( r \) is the radius of the circle (in this case, 3 units).

1. Substitute the values into the formula:
   \[
   \text{Length of Arc} = \left( \frac{42}{360} \right) \times 2\pi \times 3
   \]

2. Simplify inside the parentheses:
   \[
   \text{Length of Arc} = \left( \frac{42}{360} \right) \times 6\pi
   \]

3. Calculate the fraction:
   \[
   \frac{42}{360} = \frac{7}{60}
   \]

4. Substitute back into the equation:
   \[
   \text{Length of Arc} = \left( \frac{7}{60} \right) \times 6\pi
Transcribed Image Text:### Problem Statement In circle \( S \) with \( m\angle RST = 42^\circ \) and \( RS = 3 \) units, find the length of arc \( RT \). Round to the nearest hundredth. ### Diagram Below the problem statement, there is a diagram of a circle labeled \( S \) with points \( R \) and \( T \) on the circumference. Two line segments, \( RS \) and \( ST \), represent radii of the circle and are both 3 units long. The angle between these two radii, \( \angle RST \), is marked as \( 42^\circ \). #### Circle Diagram Explanation - Point \( S \) is the center of the circle. - Point \( R \) is on the circumference of the circle. - Point \( T \) is also on the circumference of the circle. - Both \( RS \) and \( ST \) are radii of the circle with a length of 3 units. - The angle \( \angle RST \) formed by the radii \( RS \) and \( ST \) is \( 42^\circ \). ### Solving the Problem To find the length of arc \( RT \), you can use the following formula: \[ \text{Length of Arc} = \left( \frac{\theta}{360} \right) \times 2\pi r \] where: - \( \theta \) is the central angle in degrees (in this case, \( 42^\circ \)). - \( r \) is the radius of the circle (in this case, 3 units). 1. Substitute the values into the formula: \[ \text{Length of Arc} = \left( \frac{42}{360} \right) \times 2\pi \times 3 \] 2. Simplify inside the parentheses: \[ \text{Length of Arc} = \left( \frac{42}{360} \right) \times 6\pi \] 3. Calculate the fraction: \[ \frac{42}{360} = \frac{7}{60} \] 4. Substitute back into the equation: \[ \text{Length of Arc} = \left( \frac{7}{60} \right) \times 6\pi
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