In circle J with mZHJK = 48 and HJ = 11 units, find the length of arc HK. %3D Round to the nearest hundredth. H K J

Mathematics For Machine Technology
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ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter87: An Introduction To G- And M-codes For Cnc Programming
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Problem 23A: Write a G-code program for the counterclockwise arc with starting point (-40, -20), ending point...
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**Problem Description**

In circle \( J \) with \( m \angle HJK = 48^\circ \) and \( HJ = 11 \) units, find the length of arc \( HK \). Round to the nearest hundredth.

**Diagram Explanation**

The image shows a circle centered at point \( J \). Inside the circle, there are two points, \( H \) and \( K \), on the circumference. Line segments \( HJ \) and \( JK \) are drawn, forming an angle \( \angle HJK \) at the center \( J \). The measure of \( \angle HJK \) is given as \( 48^\circ \).

**Solution Steps**

1. **Calculate the Circumference of the Circle:**
   The circumference \( C \) of the circle is given by \( C = 2\pi r \).
   
2. **Find the Length of Arc \( HK \):**
   The length of arc \( HK \) can be found as a fraction of the circumference. Since the angle \( \angle HJK \) is \( 48^\circ \), we use the formula for the arc length:
   \[
   \text{Arc Length} = \left( \frac{\theta}{360} \right) \times 2\pi r
   \]
   Substituting the given values \( \theta = 48^\circ \) and \( HJ = 11 \) units:

   \[
   \text{Arc Length} = \left( \frac{48}{360} \right) \times 2\pi \times 11
   \]

3. **Simplify and Calculate:**
   Simplifying inside the parenthesis first:

   \[
   \left( \frac{48}{360} \right) = \frac{4}{30} = \frac{2}{15}
   \]

   Then substitute this into the formula:

   \[
   \text{Arc Length} = \left( \frac{2}{15} \right) \times 2\pi \times 11
   \]

   Simplifying further:

   \[
   \text{Arc Length} = \frac{4\pi \times 11}{15} = \frac{44\pi}{15}
   \]

   Using \( \pi \approx 3.14 \):

   \[
Transcribed Image Text:**Problem Description** In circle \( J \) with \( m \angle HJK = 48^\circ \) and \( HJ = 11 \) units, find the length of arc \( HK \). Round to the nearest hundredth. **Diagram Explanation** The image shows a circle centered at point \( J \). Inside the circle, there are two points, \( H \) and \( K \), on the circumference. Line segments \( HJ \) and \( JK \) are drawn, forming an angle \( \angle HJK \) at the center \( J \). The measure of \( \angle HJK \) is given as \( 48^\circ \). **Solution Steps** 1. **Calculate the Circumference of the Circle:** The circumference \( C \) of the circle is given by \( C = 2\pi r \). 2. **Find the Length of Arc \( HK \):** The length of arc \( HK \) can be found as a fraction of the circumference. Since the angle \( \angle HJK \) is \( 48^\circ \), we use the formula for the arc length: \[ \text{Arc Length} = \left( \frac{\theta}{360} \right) \times 2\pi r \] Substituting the given values \( \theta = 48^\circ \) and \( HJ = 11 \) units: \[ \text{Arc Length} = \left( \frac{48}{360} \right) \times 2\pi \times 11 \] 3. **Simplify and Calculate:** Simplifying inside the parenthesis first: \[ \left( \frac{48}{360} \right) = \frac{4}{30} = \frac{2}{15} \] Then substitute this into the formula: \[ \text{Arc Length} = \left( \frac{2}{15} \right) \times 2\pi \times 11 \] Simplifying further: \[ \text{Arc Length} = \frac{4\pi \times 11}{15} = \frac{44\pi}{15} \] Using \( \pi \approx 3.14 \): \[
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