In circle J with MZHJK = 46 and HJ Round to the nearest hundredth. 20 units, find the length of arc HK. %3D H K J 75°F A D 40 P Type here to search

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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### Finding the Length of an Arc in a Circle

**Problem Statement:**

In circle \( J \) with \( m \angle HJK = 46^\circ \) and \( HJ = 20 \) units, find the length of arc \( HK \). Round to the nearest hundredth.

**Diagram Explanation:**

The image shows a circle with center \( J \). Two points \( H \) and \( K \) are marked on the circumference of the circle. The radius \( HJ \) measures 20 units. The central angle \( \angle HJK \) is \( 46^\circ \).

**Solution Steps:**

To find the length of arc \( HK \), we will follow these steps:

1. **Calculate the circumference of the circle:**

   The circumference \( C \) of a circle is given by the formula:
   \[
   C = 2 \pi r
   \]
   where \( r \) is the radius of the circle.

   Given:
   \[
   r = 20 \, \text{units}
   \]
   Therefore,
   \[
   C = 2 \pi \times 20 = 40 \pi \, \text{units}
   \]

2. **Calculate the fraction of the circle represented by the angle \( \angle HJK \):**

   The angle \( \angle HJK = 46^\circ \) forms a fraction of the entire circle which is \( 360^\circ \). This fraction is calculated as:
   \[
   \frac{46}{360}
   \]

3. **Calculate the length of arc \( HK \):**

   The length of an arc \( s \) is given by the product of the fraction of the circle and the circumference \( C \):
   \[
   s = \left( \frac{46}{360} \right) \times 40\pi
   \]

   Performing the calculation:
   \[
   s = \left( \frac{46}{360} \right) \times 40 \pi \approx 5.078 \, \text{units}
   \]

Therefore, the length of arc \( HK \) is approximately \( 5.08 \) units when rounded to the nearest hundredth.

**Graph/Diagram Description:**

The diagram includes a circle centered at point \( J \). Two radii \( HJ \
Transcribed Image Text:### Finding the Length of an Arc in a Circle **Problem Statement:** In circle \( J \) with \( m \angle HJK = 46^\circ \) and \( HJ = 20 \) units, find the length of arc \( HK \). Round to the nearest hundredth. **Diagram Explanation:** The image shows a circle with center \( J \). Two points \( H \) and \( K \) are marked on the circumference of the circle. The radius \( HJ \) measures 20 units. The central angle \( \angle HJK \) is \( 46^\circ \). **Solution Steps:** To find the length of arc \( HK \), we will follow these steps: 1. **Calculate the circumference of the circle:** The circumference \( C \) of a circle is given by the formula: \[ C = 2 \pi r \] where \( r \) is the radius of the circle. Given: \[ r = 20 \, \text{units} \] Therefore, \[ C = 2 \pi \times 20 = 40 \pi \, \text{units} \] 2. **Calculate the fraction of the circle represented by the angle \( \angle HJK \):** The angle \( \angle HJK = 46^\circ \) forms a fraction of the entire circle which is \( 360^\circ \). This fraction is calculated as: \[ \frac{46}{360} \] 3. **Calculate the length of arc \( HK \):** The length of an arc \( s \) is given by the product of the fraction of the circle and the circumference \( C \): \[ s = \left( \frac{46}{360} \right) \times 40\pi \] Performing the calculation: \[ s = \left( \frac{46}{360} \right) \times 40 \pi \approx 5.078 \, \text{units} \] Therefore, the length of arc \( HK \) is approximately \( 5.08 \) units when rounded to the nearest hundredth. **Graph/Diagram Description:** The diagram includes a circle centered at point \( J \). Two radii \( HJ \
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